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3 years ago

Which table represents the statement “Brian rides a bicycle at a rate of 12 meters per second”?

Mathematics

2 answers:

inna [77]3 years ago

6 0

Answer:

Its B

Step-by-step explanation:

i did test

kvasek [131]3 years ago

4 0

Yes! I agree with the person above, It’s B

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A least squares regression line was calculated to relate the length (cm) of newborn boys to their weight in kg. The relationshi

maks197457 [2]

Answer:

58.6% of the variation in length (in cm) of new born boys and their weight (in kg) is explained by the line of best fit.

Step-by-step explanation:

Given the following :

R² value = 58.6% comparing the length (cm) of new born boys to their weight (kg)

The R² value is called the Coefficient of determination. It is obtained by taking the square of the correlation Coefficient (R). The value gives the proportion of Variation between the independent and dependent variables which is explained by regression line. In the scenario above, the R² value means that 58.6% of the variation in length in centimeter of new born boys and their weight (in kg) is explained by the line of best fit. While (100% - 58.6% = 41.4%) is due to other factors.

8 0

3 years ago

Solve: 3/4 (5 f - 3) = 3/8 F=?

VMariaS [17]

Answer:

f= 0.7

Step-by-step explanation:

Multiply by reciprocal on both sides: 4/3 * 3/4(5f-3) = 3/8 * 4/3 f

Then, you are left with: 5f-3 = 1/2

Then you subtract by three on both sides to get: 5f=3.5

Finally, divide by 5 on both sides to get: f=.07

3 0

3 years ago

Which of the following statements is true of a reflection?

zhuklara [117]

I think the correct answers from the choices listed above are the first and the fourth option. The statements that are true about a reflection would be that it is an isometry and the it flips a plane about a fixed line. A reflection over a line k (notation rk) is a transformation in which each point of the original figure (pre-image) has an image that is the same distance from line k.

7 0

3 years ago

Find each Of change. Round to the nearest whole percent if necessary. State whether the percent Of change is an increase or 1. O

Alenkasestr [34]

Answer:

1. The percentage change is 74% and it is a percentage decrease

2. The percentage change is 15% and it is a percentage decrease

3. The percentage change is 20% and it is a percentage decrease

4. The percentage change is 43% and it is a percentage increase

5. The percentage change is 40% and it is a percentage decrease

6. The percentage change is 39% and it is a percentage decrease

Step-by-step explanation:

Given

$1.\ Original = 5; New = 1.3$

$2.\ Original = 160; New = 136$

$3.\ Original = 15; New = 12$

$4.\ Original = 7; New = 10$

$5.\ Original = $30; New = $18$

$6.\ Original = 9.6; New = 5.9$

Required

Determine the percentage change and state whether it's an increase or decrease

Percentage change is calculated as:

$\%Change = \frac{New - Original}{Original} * 100\%$

$1.\ Original = 5; New = 1.3$

$\%Change = \frac{1.3 - 5}{1.3} * 100\%$

$\%Change = \frac{-3.7}5} * 100\%$

$\%Change = \frac{-3.7 * 100\%}{5}$

$\%Change = \frac{-370\%}{5}$

$\%Change = -74\%$

The percentage change is 74% and it is a percentage decrease

$2.\ Original = 160; New = 136$

$\%Change = \frac{136 - 160}{160} * 100\%$

$\%Change = \frac{-24}{160} * 100\%$

$\%Change = \frac{-24 * 100\%}{160}$

$\%Change = \frac{-2400\%}{160}$

$\%Change = -15\%$

The percentage change is 15% and it is a percentage decrease

$3.\ Original = 15; New = 12$

$\%Change = \frac{12- 15}{15} * 100\%$

$\%Change = \frac{-3}{15} * 100\%$

$\%Change = \frac{-3* 100\%}{15}$

$\%Change = \frac{-300\%}{15}$

$\%Change = -20\%$

The percentage change is 20% and it is a percentage decrease

$4.\ Original = 7; New = 10$

$\%Change = \frac{10- 7}{7} * 100\%$

$\%Change = \frac{3}{7} * 100\%$

$\%Change = \frac{3* 100\%}{7}$

$\%Change = \frac{300\%}{7}$

$\%Change = 43\%$ -- (approximated)

The percentage change is 43% and it is a percentage increase

$5.\ Original = $30; New = $18$

$\%Change = \frac{18- 30}{30} * 100\%$

$\%Change = \frac{-12}{30} * 100\%$

$\%Change = \frac{-12* 100\%}{30}$

$\%Change = \frac{-1200\%}{30}$

$\%Change = -40\%}$

The percentage change is 40% and it is a percentage decrease

$6.\ Original = 9.6; New = 5.9$

$\%Change = \frac{5.9- 9.6}{9.6} * 100\%$

$\%Change = \frac{-3.7}{9.6} * 100\%$

$\%Change = \frac{-3.7* 100\%}{9.6}$

$\%Change = \frac{-370\%}{9.6}$

$\%Change = -39\%$ -- (approximated)

The percentage change is 39% and it is a percentage decrease

5 0

3 years ago

Let f(x) = -5e^(-x/3) Find f^(6) (1)

Luba_88 [7]

Let's take the first derivative:

$f'(x) = (-5e^{-x/3})' = -5 \times (e^{-x/3})' = -5e^{-x/3} \times \left(-\dfrac{1}{3}\right) = \dfrac{5}{3}e^{-x/3}.$

Notice that we can write this as:

$f'(x) = -\dfrac{f(x)}{3}.$

By taking the derivative of both sides $n$ times, we get:

$f^{(n+1)}(x) = -\dfrac{f^{(n)}}{3}.$

This means that each time you take a derivative, a factor of $-\dfrac{1}{3}$ will appear. So we conclude that:

$f^{(n)}(x) = \left(-\dfrac{1}{3}\right)^nf(x).$

Taking $n=6$ and $x=1$ , we get:

$f^{(6)}(1) = \left(-\dfrac{1}{3}\right)^6 f(1) = \dfrac{-5e^{-1/3}}{729} = -\dfrac{5}{729}e^{-1/3}.$

So we finally get:

$\boxed{-\dfrac{5}{729}e^{-1/3}}.$

6 0

3 years ago