Answer:
a=–2, 3
Step-by-step explanation:
r(a)=20
a²–a+14=20===> a²–a–6=0===> (a–3)(a+2)
Use the product, power, and chain rules.
Differentiate both sides:
Product rule:
Power rule for the first derivative, power and chain rules for the second one:
One last applicaton of power rule:
You could stop here, or continue and simplify the result by factorizing:
Answer:
Step-by-step explanation:
Since the graph passes through both (-8,0) and (-2,0), the vertex's x value must be the average of the two, or -5. To determine the y value, you need the third point, (-6,4). In a parabola without any dilation or stretching, the difference between the y value of the point 1 unit to the side of the vertex and the point 3 units away is 9-1=8. However, here it is 4, meaning that this graph has a dilation of 1/2. This means that the vertex has a y value of 9/2=4.5, and that the vertex is (-5,4.5). From here, you can simply plug in the known values to get the vertex form, and then convert to standard. , which in standard form is . Hope this helps!
The equations classified according to the number of solutions are given as follows:
- No solution: -3(3q + 4) = -6q + 12
- One solution: -2(3n - 4) = -6n - 4
- Infinitely many solutions: 8z - 4 = 8z - 4
<h3>How many solutions does the equation 4(2z - 1) = 8z - 4 has?</h3>
We solve the equation, hence:
4(2z - 1) = 8z - 4
8z - 4 = 8z - 4
Equivalent, hence they have infinitely many solutions.
<h3>How many solutions does the equation -2(3n - 4) = -6n - 4 has?</h3>
-2(3n - 4) = -6n - 4
-6n + 8 = -6n - 4
0 = -12, which is false, hence it has no solutions.
<h3>How many solutions does the equation -3(3q + 4) = -6q - 12 has?</h3>
-3(3q + 4) = -6q + 12
-9q - 12 = -6q + 12
3q = -24
q = -8.
One solution.
More can be learned about the solutions of an equation at brainly.com/question/24342899
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Answer:
Yes it is a function because all the x values are different. If there were two or more of the same number in the x list it would not be a function. And it doesn't matter for the y list if two or more of the numbers are the same.