<h3>
Answer:<u>
3
/6 ÷ 9
/18 is 1
/1
</u></h3>
Step-by-step explanation: Steps for dividing fractions
Find the reciprocal of the divisor
<u>Reciprocal of 9/
18
: 18
/9 Now, multiply it with the dividend
So, 3/
6 ÷ 9/18 = 3
/6 × 18
/9
= 3 × 18/
6 × 9 = 54/
54
</u>
<u>After reducing the fraction, the answer is </u>
<u>1
/1</u>
<h2 />
Answer:
[A] use the complementary relationship between sine and cosine to rewrite sin(x + y) as cos(pi/2-(x+y)). apply the cosine sum identity. then simplify using sin(–y) = –sin(y) and cos(–y) = cos(y).
Step-by-step explanation:
i got it right
screw that other person l0l
note that sin(-x)=-sin(x) and cos(-x)=cos(x)
so sin(-y)=-sin(y) and cos(-y)=cos(y)
or something like that idfk
Answer:
1. Not True
2. Not True
3. Not True
4. Not True
5. True
Step-by-step explanation:
As given,
1.
2 + 3 = 9
⇒ 5 = 9
Not True
2.
4 > 5 + 7
⇒4 > 12
Not True
3.
9 = 12 + 2
⇒9 = 14
Not True
4.
2 - 3 ≥ 2
-1 ≥ 2
Not True
5.
61 ≠ 5 - 12
⇒61 ≠ -7
True
The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
Answer:
y<
x+1 is inequality shown on graph.
Step-by-step explanation:
The graph shows representation of inequality,
Here, Line passes through points say, A(3,0) and B(0,1)
The slope of line is given by m=
m=
m=
m=
and Y-intercept is c=1
The equation of line is given by y=mx+c
y=
x+1 is equation of line in graph.
To decide which side you are going to shaded area on the graph
Take test of origin.
If (0,0) is statisfy the equation then, shaded the graph towards the origin.
Let suppose,
Take, y<
x+1
0<
(0)+1
0<1
TRUE,
Therefore, y<
x+1 is inequality shown on graph.