Answer:
option A, option C, option D
Step-by-step explanation:
a) 1 ÷ m/6
can be written as
÷ 
b) sides in (m/6) will change if both has to multiply
c) 1 ÷ m/6
can be written as
1 * 6/m
1(
) and wont make change to answer. so matches with the question.
d)
1 ÷ m/6
1 * 6/m
1 * 6 * 
6 * 
6 ÷ m ..therefore true
e)
1 ÷ m/6
1 * 6/m
6/m ....does not match or can be converted to the following so wrong
- Therefore A, C, D are correct and B and E is wrong.
I think c.
bc when u add it up and stuff
N = d - 5
2n/(d + 16) = n/d - 1/3 n/d
2n/(d + 16) = 2/3 n/d Divide by 2n
1 / (d + 16) = 1/3 d
Here's the tricky part.
d + 16 = 3d the two denominators are equal. the numerators are both 1.
16 = 2d
d = 8
so the numerator is d - 5
n = 8 - 5
n = 3
Let's see if it checks out.
n = 3
d = 8
2*3 = 6
8 + 16 = 24
New fraction 6/24 = 1/4
(3/8 - 1/3 ) = 1/8
3/8 - 1/8 = 1/4 so it checks with the original conditions put on it.
Answer:
h=58.5/b
Step-by-step explanation:
This isn't necessarily possible, unless you know the base, but I can solve it with what we have, understanding the answer will contain variables:
The formula for the area of a triangle is A=1/2bh
117=(1/2)bh
58.5=bh
h=58.5/b
I'm not sure if this is the answer you were looking for, but I hope it helps
Question:
What is the common ratio between successive terms in the sequence?
27, 9, 3, 1
Answer:
common ratio = 
Step-by-step explanation:
In a geometric progression, the common ratio, r, is the ratio of a term in the sequence to a preceding term in that same sequence. In other words, the common ratio is found by dividing a term by the term just before it. For example, if the geometric sequence is:
a, b, c, d...
The common ratio is found by any of the following;
r =
----------(i)
r =
-----------(ii)
r =
------------(iii)
Any of equations (i) through (iii) will give the common ratio of the sequence.
============================================================
Now, from the question, the given sequence is;
27, 9, 3, 1
To get the common ratio, just divide the second term (9) by the first term (27) i.e
r =
= 
OR
You can also divide the third term (3) by the second term (9). i.e
r =
= 
OR
You can choose to divide the fourth term (1) by the third term (3). i.e
r = 
Which ever adjacent terms you choose gives you the same result. Therefore, the common ratio of the given sequence is 