A = 28000(0.9275)^5
a = 19219
$19,219 is the answer
Hoped this helped
Answer:
0.36427
Step-by-step explanation:
Mean = λ = 18 messages per hour
P(X = x) = (e^-λ)(λ⁻ˣ)/x!
P(X ≤ x) = Σ (e^-λ)(λ⁻ˣ)/x! (Summation From 0 to x)
But the probability required is that the messages thay come in an hour is between 15 and 20, that is, P(15 < X < 20)
P(15 < X < 20) = P(X < 20) - P(X ≤ 15)
These probabilities will be evaluated using a cumulative frequency calculator.
P(X < 20) = 0.65092
P(X ≤ 15) = poissoncdf(18, 15) = 0.28665
P(15 < X < 20) = P(X < 20) - P(X ≤ 15) = 0.65092 - 0.28665 = 0.36427.
You can use the Poisson distribution calculator here
https://stattrek.com/online-calculator/poisson.aspx
Answer:
The correct answer is there are 15 samples each of size 4 to choose from the population and the population mean is 27.
Step-by-step explanation:
Total number of lottery tickets = 6
Number of samples of size 4 that can be drawn from this population of 6 lottery numbers are = ![\left[\begin{array}{ccc}6\\4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C4%5Cend%7Barray%7D%5Cright%5D)
= 15.
Now the population mean is given by 
× ∑ x , where n is the number of lottery tickets and ∑ x is the sum of the lottery numbers.
Summation of the lottery ticket numbers is 162
Thus the population mean is given by 
= 27.
