let's firstly convert the mixed fractions to improper fractions and then divide.
![\bf \stackrel{mixed}{1\frac{1}{4}}\implies \cfrac{1\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{5}{4}}~\hfill \stackrel{mixed}{3\frac{4}{5}}\implies \cfrac{3\cdot 5+4}{5}\implies \stackrel{improper}{\cfrac{19}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{4}\div\cfrac{19}{5}\implies \cfrac{5}{4}\cdot \cfrac{5}{19}\implies \cfrac{25}{76}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B1%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B1%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B5%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B4%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%205%2B4%7D%7B5%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B5%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B5%7D%7B4%7D%5Cdiv%5Ccfrac%7B19%7D%7B5%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B5%7D%7B19%7D%5Cimplies%20%5Ccfrac%7B25%7D%7B76%7D)
Answer: 49
Step-by-step explanation:
From your question, I think you mean the largest number. The answer is given below.
Let the five consecutive odd numbers be:
a, a+2, a+4, a+6 and a+8.
Thee sum of the first and double the last is 139. This can be written as:
a + 2(a+8) = 139
a + 2a + 16 = 139
3a + 16 = 139
3a = 139 - 16
3a = 123
a = 123/3
a = 41
The first number = 41
The largest number = a+8 = 41 + 8 = 49.
Answer:
16
Step-by-step explanation:i took the edge assignment