Answer:
Explanation:
During mitosis, the chromosomes are distributed equally in the resulting chromosome. The chromosome number was doubled in the S phase of the interphase and the cell is ready for mitosis. The chromosomes are more condensed and twisted in prophase. It is also double in length. During the metaphase, the chromosomes are arranged in the metaphase plate. The microtubules from the centriole attach to the centromere of each chromosome and pull them towards the pole.
Thus each chromatid pulls apart and migrates towards the poles. The nuclear membrane and nucleus disappear during mitosis. At the end of telophase, the daughter cells contain an equal number of chromatids as in the parent cell.
Sometimes the microtubules of centrioles do not function properly and fail to pull the chromosomes equally to the cells. Thus one of the daughter cells contains more chromosomes and another fewer chromosomes. This occurs in anaphase. This results in the non-disjunction of chromosomes.
Sometimes centromere splits transversely instead of longitudinal division. This results in the formation of 2 daughter chromosomes of unequal length. This is called the isochromosomes.
The number of chromosomes distributed in the daughter cells results in a normal cell or any genetic disorder. The main function of mitosis to produce daughter cells having an equal number of chromosomes present in the parent cell.
D. The data for the average heights of the plants in trials 1 and 3 contains errors
Explanation: Please double check my answer.
Answer:
the number of big fish would increase
Explanation:
when theres a bunch of small fish, that is more food for the big fish ao the population of big fish will increase
Just like the name suggests it's the second consumer in a food web or food chain that eats the primary consumers or the producers.
Answer:
The correct answer would be - there will be wild type and double mutant (contains both the deletion mutation and the point mutation)
Explanation:
It is mention that the deletion mutation and point mutation are non-overlapping or no overlapping regions in the phage genome. A crossing-over event between the regions of these two mutations would get wild-type which means there would be neither point mutation nor deletion mutation and other would be a double mutant that contains both mutation - the point mutation and the deletion mutation.
Thus, the correct answer is - there will be wild type and double mutant (contains both the deletion mutation and the point mutation)
