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3 years ago

Determine whether the three side lengths form a triangle. 3,5,7

Mathematics

1 answer:

Ann [662]3 years ago

8 0

Yes. Because the sum of the two small numbers are bigger than the longest side.

3+5 >7

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∠1 and ∠2 are supplementary angles. ∠1 and ∠3 are vertical angles. If m ∠2=72 degrees, then find m ∠3

JulsSmile [24]

Answer:

m<3 = 108

Step-by-step explanation:

Since <1 and <2 are supplementary, the equation is:

<1 + <2 = 180

Since <1 and <3 are vertical angles. the equation is:

<1 = <3

To find m<3:

<2 + <3 = 180

72 + <3 = 180

<3 = 180 - 72

<3 = 108

3 0

3 years ago

Read 2 more answers

I need to find two pairs of integers whose sum is -6

Allisa [31]

-8 and 2 is one pair

another could be -4 and -2.

6 0

3 years ago

Find the slope of the line through each pair of points.3) (3, -10), (14, -10)

mariarad [96]

Answer:

the second answer

Step-by-step explanation:

I took the test

4 0

3 years ago

Be sure to answer all parts. List the evaluation points corresponding to the midpoint of each subinterval to three decimal place

gayaneshka [121]

Answer:

The Riemann Sum for $\int\limits^5_4 {x^2+4} \, dx$ with n = 4 using midpoints is about 24.328125.

Step-by-step explanation:

We want to find the Riemann Sum for $\int\limits^5_4 {x^2+4} \, dx$ with n = 4 using midpoints.

The Midpoint Sum uses the midpoints of a sub-interval:

$\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f\left(\frac{x_0+x_1}{2}\right)+f\left(\frac{x_1+x_2}{2}\right)+f\left(\frac{x_2+x_3}{2}\right)+...+f\left(\frac{x_{n-2}+x_{n-1}}{2}\right)+f\left(\frac{x_{n-1}+x_{n}}{2}\right)\right)$

where $\Delta{x}=\frac{b-a}{n}$

We know that a = 4, b = 5, n = 4.

Therefore, $\Delta{x}=\frac{5-4}{4}=\frac{1}{4}$

Divide the interval [4, 5] into n = 4 sub-intervals of length $\Delta{x}=\frac{1}{4}$

$\left[4, \frac{17}{4}\right], \left[\frac{17}{4}, \frac{9}{2}\right], \left[\frac{9}{2}, \frac{19}{4}\right], \left[\frac{19}{4}, 5\right]$

Now, we just evaluate the function at the midpoints:

$f\left(\frac{x_{0}+x_{1}}{2}\right)=f\left(\frac{\left(4\right)+\left(\frac{17}{4}\right)}{2}\right)=f\left(\frac{33}{8}\right)=\frac{1345}{64}=21.015625$

$f\left(\frac{x_{1}+x_{2}}{2}\right)=f\left(\frac{\left(\frac{17}{4}\right)+\left(\frac{9}{2}\right)}{2}\right)=f\left(\frac{35}{8}\right)=\frac{1481}{64}=23.140625$

$f\left(\frac{x_{2}+x_{3}}{2}\right)=f\left(\frac{\left(\frac{9}{2}\right)+\left(\frac{19}{4}\right)}{2}\right)=f\left(\frac{37}{8}\right)=\frac{1625}{64}=25.390625$

$f\left(\frac{x_{3}+x_{4}}{2}\right)=f\left(\frac{\left(\frac{19}{4}\right)+\left(5\right)}{2}\right)=f\left(\frac{39}{8}\right)=\frac{1777}{64}=27.765625$

Finally, use the Midpoint Sum formula

$\frac{1}{4}(21.015625+23.140625+25.390625+27.765625)=24.328125$

This is the sketch of the function and the approximating rectangles.

5 0

4 years ago

Find the minimum point for the function f(x) = |2x - 1| (0, ½) (½, 0) (0, -½) (-½, 0)

torisob [31]

Minimum point of an absolute value function is when f(x) = 0
0 = <span>|2x - 1|
2x</span> - 1 = 0
2x = 1
x = 1/2

Minimum point is (1/2, 0)

6 0

3 years ago