Question

The diameter of a circle is 7 in. Find its area to the nearest tenth.

Answer 1

Answer:

$38.5in^{2}$

Step-by-step explanation:

Area of a circle = $\pi r^{2}$

Radius of circle = $7\times\frac{1}{2}$

$= 3.5$

So, $\pi r^{2} = \pi \times 3.5^{2}$

$= \pi \times 12.25$

$= 38.48451...$

$= 38.5$ ($1$ d.p)

$\therefore$ the area of the circle is $38.5 in^{2}$ rounded to the nearest tenth place.

Hope this helps :)

Answer 2

Answer:

38.46≅38.5

Step-by-step explanation:

Area = П

r = diameter / 2

= 7/2

r =3.5

Π= 3.14

Area = 3.14 × = 38.46

to the nearest tenth = 38.5 in