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3 years ago

Which is equivalent to (9y2 – 4x)(9y2 + 4x), and what type of special product is it?

1 answer:

7 0

This is an example of the difference of squares.

$a^2 - b^2 = (a-b)(a+b)$

So to find the product of (9y² – 4x)(9y² + 4x), we use the formula for the difference of squares.

 $(9y^2 - 4x)(9y^2 + 4x)\\\\=(9y^2)^2 -(4x)^2\\\\=\boxed{\bf{81y^4 - 16x^2}}$

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Which logorithmic equation is equivalent to the exponential equation below? e^a=60

Alex73 [517]

Answer:

a = ln(60)

Step-by-step explanation:

4 0

3 years ago

What is this fraction as a decimal?

tiny-mole [99]

0.4444444444444
is the answer for your question it repeats so your gonna want to put a bar notation.

8 0

3 years ago

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

yanalaym [24]

Answer:

Step-by-step explanation:

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

A model shows a total of c cups divided into 10 sections, each labeled 2 and 1 fourth.

Part A

Which equation models the total number of cups of flour, c, Henry needs?

c+214=10

214×c=10

10+c=214

214×10=c

Part B

How many cups of flour does Henry need?

2014cups

2212cups

2434cups

2512cups

Part C

Estimate how much flour Henry would need to make 15 batches of cookies. Explain.

I would round 214 to 2, so Henry would need about 30 cups of flour.

I would round 214 to 3, so Henry would need about 45 cups of flour.

I would round 214 to 1, so Henry would need about 15 cups of flour.

I would round 214 to 234, so Henry would need about 30 cups of flour.

8 0

3 years ago

Find the product of the sum of 3/5 and 1% and

dybincka [34]

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

8 0

3 years ago

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

3 years ago