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lora16 [44]
3 years ago
13

Which is equivalent to (9y2 – 4x)(9y2 + 4x), and what type of special product is it?

Mathematics
1 answer:
QveST [7]3 years ago
7 0
This is an example of the difference of squares.

a^2 - b^2 = (a-b)(a+b)

So to find the product of <span>(9y</span>²<span> – 4x)(9y</span>²<span> + 4x), we use the formula for the difference of squares.

</span>(9y^2 - 4x)(9y^2 + 4x)\\\\=(9y^2)^2 -(4x)^2\\\\=\boxed{\bf{81y^4 - 16x^2}}<span>
</span>
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Write the equation of the line with an x-intercept at (0,2) and perpendicular to 3x+4y=12.
juin [17]

First you normalize 3x+4y=12 into y = -3/4 x + 3 (dividing by 4).

Then you observe that the slope of the line is -3/4 (it's always the factor with the x). A perpendicular line has the reciprocal slope. Reciprocal means inverted and negated. So -3/4 becomes +4/3.

The equation will thus look like y = 4/3 x + b. To find b, we fill in the given x intercept (0,2), (we get 2 = 4/3 * 0 + b). With x=0, b must be 2.

So the equation is: y = 4/3 x + 2

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2 years ago
Using substitution to solve the system below, what expression should be substituted into the first equation? 2x-4y=-4 and x+2y=8
inna [77]

Answer:

Given the system of equation:

2x-4y=-4                    ......[1]

x+2y=8                      ......[2]

we can rewrite equation [2] as;

x = 8-2y                ......[3]

Substitute equation [3] into [1] to eliminate x, and solve for y;

2(8-2y)-4y = -4

Using distributive property: a\cdot (b+c) = a\cdot b+ a\cdot c

16-4y -4y = -4

Combine like terms;

16 - 8y = -4

Add 4 to both sides we have;

20 - 8y = 0

Add 8y to both sides we have;

20 = 8y

Divide 8 to both sides we have;

y = 2.5

Substitute the y-value in [3] we have;

x = 8-2(2.5)

x = 8 - 5 = 3

Therefore, the  expression should be substituted into the first equation is, x = 8-2y  and also the value of x = 3 and y = 2.5

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3 years ago
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Tomtit [17]
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 brainliest answer <br>points question in the photo!!
ivolga24 [154]

..................#2

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