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nikitadnepr [17]
3 years ago
15

Evaluate the following expressions if ×=2,y=3 and Z=4. a.4×+×-3over ×+10 b.2y-5yover y+5. c.yz-×. d.9+y+zover y+2​

Mathematics
1 answer:
sammy [17]3 years ago
6 0

Answer:

A= 7 11/12 or 7.916 or  95.12

B= 4 1/8 or 4.125 or 33/8

C=  12 4/5 or 12.8 or 64/5

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kati45 [8]

Answer:

x ≥ -1

Step-by-step explanation:

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7 0
3 years ago
What is the solution for the equation 14.8 equals n -0.3
vodomira [7]

Hello there!

14.8=n-0.3

Answer:

\boxed{n=15.1=15.0}

You can also round up to the nearest tenths is 15.1 to 15.0 and its going to be stay.

Step-by-step explanation:

First you had to switch sides of equation form.

n-0.3=14.8

Then you add by 0.3 from both sides of equation form.

n-0.3+0.3=14.8+0.3

And finally, simplify by equation. You can also cross out by -0.3+0.3 and it gave us equal to zero. Then you add 14.8+0.3 and it equal to 15.1. You had to used their variable and its should be the right answer.

n=15.1

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

6 0
3 years ago
What's 2 to the negative 6 power times 2 to the negative 10th power
mafiozo [28]
When multiplying numbers with exponents, add the exponents.

So the answer is 2^-16
7 0
3 years ago
Read 2 more answers
Can anybody help me with 1 and 2
Anit [1.1K]
1) x \geq 96
2) x\ \textless \ 38

Here, the variable x can assume any value, and usually an inequality presented like this has x as a stand-in for all real numbers. If we really wanted to make that fact clear, we could write the two inequalities like this:

x \geq 96, x\in\mathbb{R}\\ x\ \textless \ 38, x\in\mathbb{R}

Formally, you'd read x\in\mathbb{R} as "x is an element of the set of real numbers," which is a fancy way of saying that x can be any real number.
8 0
3 years ago
3. Find the value of a and b when<br>5+√6/5-√6 = a+b√6​
mr Goodwill [35]

The answer for A is,

a = 5 +  \frac{ \sqrt{6} }{ \sqrt{5} }  -  \sqrt{6}  -  \sqrt{6b}

And the answer for B is,

b = - 1 +  \frac{5 +  \frac{ \sqrt{6} }{ \sqrt{5} } - a  }{  \sqrt{6} }

hope it helps.

sorry of its wrong.

4 0
3 years ago
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