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Advocard [28]
4 years ago
15

20 points!!! I’ll give brainliest!

Mathematics
2 answers:
shusha [124]4 years ago
5 0
ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)

Thus,DE=CE (By CPCTC)

HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!!
OLEGan [10]4 years ago
3 0

Answer:

1. AD ≅ BC    [Given]

2. ∠ADC ≅ ∠BCD    [Given]

3. DC ≅ DC    [reflexive property]

4. ΔADC ≅ ΔBCD    [SAS]

5. ∠DAE ≅ ∠CBE    [CPCTC]

6. ∠DEA ≅ ∠CEB    [def. of vertical angles]  

7. ∠DEA ≅ ∠CEB    [vertical angles theorem]

8. ΔAED ≅ ΔBEC    [AAS]

9. DE ≅ CE    [CPCTC]

Step-by-step explanation:

Just finished mine :D

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PLZ ANSWER THIS ITS DUE TODAY I WILL GIVE BRAINLEST!!!!
Sever21 [200]

Answer:

In many instances, the lyrics to folk songs came from existing nursery rhymes or poems, and some of the nursery rhymes had variations, depending on region or time. Thus, these folk songs may have lyrics that are slightly different from those you are familiar with.

Therefore, in my opinion, I think that Nursery songs can be considered folk music.

Im so so so so sorry if this is wrong or not the answer you were looking for. i truly am. hopefully this will be good

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Ava bought a collection of hardcover novels and paid $450 including sales tax the sales tax 10% How much was the price of collec
scoray [572]

Answer:

The price of collection of novels before taxes was <u>$409.10</u>.

Step-by-step explanation:

Given:

Ava bought a collection of hardcover novels and paid $450 including sales tax.

The sales tax is 10%.

Now, to find the price of collection of novels before taxes.

Let the price of collection of novels before sales tax be x.

The price of collection of novels including sales tax = $450.

Rate of sales tax = 10%.

Now, to get the price before sales tax by putting an equation:

x=450-10\%\ of\ x

x=450-\frac{10}{100} \times x

x=450-0.10\times x

x=450-0.10x

<em>Adding both sides by 0.10</em>x<em> we get:</em>

<em />1.10x=450<em />

<em>Dividing both sides by 1.10 we get:</em>

x=\$409.10.

Therefore, the price of collection of novels before taxes was $409.10.

5 0
3 years ago
Plz help with this question i know you could do it please help​
Anon25 [30]

Answer:

The answer is 44.99

Step-by-step explanation:

divide 89.98/2= 44.99

4 0
3 years ago
Solve.<br> 13 - 2x1 = 9<br> A. X=-3<br> B. X=6<br> C. X=-3, x = 6<br> D. x = 3, x = 6
Vlada [557]

\huge\text{Hey there!}

\large\boxed{\mathsf{13 - 2x^1 = 9}}\\\\\large\boxed{\mathsf{\rightarrow 13 - 2x = 9}}\\\\\large\boxed{\rightarrow \mathsf{-2x + 13 = 9}}\\\\\large\boxed{\textbf{SUBTRACT 13 to BOTH SIDES}}\\\\\large\boxed{\mathsf{-2x + 13 - 13 = 9 - 13}}\\\\\large\boxed{\textbf{CANCEL out: 13 - 13 because it gives you 0}}\\\large\boxed{\textbf{KEEP: 9 - 13 because it help solve for the x-value}}\\\\\large\boxed{\textbf{NEW EQUATION: -2x = 9 - 13}}\\\large\boxed{\textbf{SIMPLIFY IT!}}\\\\\large\boxed{\mathsf{-2x = -4}}

\large\boxed{\textbf{DIVIDE -2 to BOTH SDES}}\\\\\large\boxed{\mathsf{\dfrac{-2x}{-2} = \dfrac{-4}{-2}}}\\\\\large\boxed{\textbf{CANCEL out: } \mathbf{\dfrac{-2}{-2}} \textbf{ because it gives you 1}}\\\\\large\boxed{\textbf{KEEP: } \bf \dfrac{-4}{-2} \textbf{ because it gives you the value of x}}\\\\\large\boxed{\textbf{NEW EQUATION: } \mathbf{x= \dfrac{-4}{-2}}}\\\\\boxed{\large\textsf{SIMPLIFY IT!}}\\\\\large\boxed{\textbf{x = 2}}

\huge\text{Therefore, your answer is: \boxed{\mathsf{x = 2}}}\huge\checkmark

\large\textbf{Good luck on your assignment \& enjoy your day!}\\\\\frak{Amphitrite1040:)}

7 0
3 years ago
Find the dimensions of a cylinder of volume 17 m3 of minimal cost if the top and bottom are made of material that costs twice as
Viefleur [7K]

Answer:

The answer is below

Step-by-step explanation:

The volume of the cylinder with radius (r) and height (h) is given as:

Volume = πr²h

17 = πr²h

h = 17 / πr²

Let k represent the cost of the side and 2k the cost of the bottom.

The area of the side = 2πrh, hence the cost of the side = k(2πrh)

The area of the top and bottom = 2πr², hence the cost of the top and bottom = 2k(2πr²)

The total cost (T) = cost of side + cost of the top and bottom

T = k(2πrh) + 2k(2πr²)

T = 2kπ(rh + 2r²)

Put h = 17/πr²

T = 2kπ (r×17/πr² + 2r²)

T = 2kπ(17/πr + 2r²)

The minimal cost is at dT/dr = 0

\frac{dT}{dr} =0=\frac{d}{dr} [2k\pi(\frac{17}{\pi r} +2r^2)]\\\\4r-\frac{17}{\pi r^2} =0\\\\4r=\frac{17}{\pi r^2}\\\\r^3=\frac{17}{4\pi }=1.35\\\\r=\sqrt[3]{1.35}\\\\r=1.1\ m\\\\h=\frac{17}{\pi r^2}  =\frac{17}{\pi (1.1)^2} \\\\h=4.42\ m

5 0
3 years ago
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