20 points!!! I’ll give brainliest!
2 answers:
ANSWER: In triangles BEC and AED 1)BC=AD(given) 2)Angle BCD= Angle ADC(given) Then,Angles BCE=Angle ADE 3)Angle BEC=Angle AED(vertically opposite angles) Thus,triangleBEC=~triangle AED( by AAS rule) Thus,DE=CE (By CPCTC) HOPE IT HELPS!!!!! PLEASE MARK BRAINLIEST!!!!!
Answer:
1. AD ≅ BC [Given ]
2. ∠ADC ≅ ∠BCD [Given ]
3. DC ≅ DC [reflexive property ]
4. ΔADC ≅ ΔBCD [SAS ]
5. ∠DAE ≅ ∠CBE [CPCTC ]
6. ∠DEA ≅ ∠CEB [def. of vertical angles ]
7. ∠DEA ≅ ∠CEB [vertical angles theorem ]
8. ΔAED ≅ ΔBEC [AAS ]
9. DE ≅ CE [CPCTC ]
Step-by-step explanation:
Just finished mine :D
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