20 points!!! I’ll give brainliest!
2 answers:
ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)
Thus,DE=CE (By CPCTC)
HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!!
Answer:
1. AD ≅ BC [Given]
2. ∠ADC ≅ ∠BCD [Given]
3. DC ≅ DC [reflexive property]
4. ΔADC ≅ ΔBCD [SAS]
5. ∠DAE ≅ ∠CBE [CPCTC]
6. ∠DEA ≅ ∠CEB [def. of vertical angles]
7. ∠DEA ≅ ∠CEB [vertical angles theorem]
8. ΔAED ≅ ΔBEC [AAS]
9. DE ≅ CE [CPCTC]
Step-by-step explanation:
Just finished mine :D
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