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Advocard [28]
3 years ago
15

20 points!!! I’ll give brainliest!

Mathematics
2 answers:
shusha [124]3 years ago
5 0
ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)

Thus,DE=CE (By CPCTC)

HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!!
OLEGan [10]3 years ago
3 0

Answer:

1. AD ≅ BC    [Given]

2. ∠ADC ≅ ∠BCD    [Given]

3. DC ≅ DC    [reflexive property]

4. ΔADC ≅ ΔBCD    [SAS]

5. ∠DAE ≅ ∠CBE    [CPCTC]

6. ∠DEA ≅ ∠CEB    [def. of vertical angles]  

7. ∠DEA ≅ ∠CEB    [vertical angles theorem]

8. ΔAED ≅ ΔBEC    [AAS]

9. DE ≅ CE    [CPCTC]

Step-by-step explanation:

Just finished mine :D

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igor_vitrenko [27]
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first, find the numeric value for 11/15
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