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2 years ago

4 yd. 8 in. + 6 yd. 6 in ?????????????

Mathematics

2 answers:

erma4kov [3.2K]2 years ago

8 0

Here , we have been asked to find sum of the expression

$4 yd. 8 in. + 6 yd. 6 in$

Here we have two different units , so we will convert it to one after adding

$4 yd. 8 in. + 6 yd. 6 in=10yd.14in.\\ \\ \text{As we know that }1in=0.0277778yd\\ \\ \Rightarrow 14in=0.388889yd\\ \\ \text{Hence we can write }\\ \\ 4 yd. 8 in. + 6 yd. 6 in=10yd.14in.=10.388889yd\\ \\ \text{After rounding we have}\\ \\ 4 yd. 8 in. + 6 yd. 6 in=10.39yd$

horrorfan [7]2 years ago

5 0

4 yd + 6 yd = 10 yd
8 in + 6 in = 14 in = 1 foot 2 in

Answer is 10 yd 1 ft 2 in

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RideAnS [48]

Answer:

Charlotte spend $\frac{1}{8}$ of day trying on jeans

Step-by-step explanation:

Charlotte spent part of day on shopping = $\frac{1}{2}$

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We are supposed to find What fraction of the day did Charlotte spend trying on jeans.

She spent fraction of the day in trying jeans = $\frac{1}{2} \times \frac{1}{4}$

She spent fraction of the day in trying jeans = $\frac{1}{8}$

Hence Charlotte spend $\frac{1}{8}$ of day trying on jeans

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2 years ago

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2 years ago

Consider the parabola y = 8x − x2. (a) find the slope of the tangent line to the parabola at the point (1, 7). 6 (b) find an equ

Brut [27]

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2 years ago

Read 2 more answers

Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a

bekas [8.4K]

9514 1404 393

Answer:

(c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
NOT linearly independent

Step-by-step explanation:

We want ...

c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

x(c1 +2c3) = 0

x²(c2 -4c3) = 0

These have an infinite set of solutions:

c1 = -2c3

c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

(c1, c2, c3) = (-2t, 4t, t)

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0

2 years ago