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ollegr [7]
3 years ago
5

Help me pls pls pls pls​

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

It has to be 21 2/3,A

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Answer:hi

Step-by-step explanation:hello

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2 years ago
100 + 5 x 4 + 4^3<br><br><br><br> Sndbdnd
trasher [3.6K]

Answer:

144

Step-by-step explanation:

100 \div 5 \times 4 + 4^3 =

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3 0
2 years ago
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Find cos B 52 b 65 a 39​
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hi

Step-by-step explanation:

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3 years ago
Let x be the price of a new car. Let n be the number of people willing to buy the car at price x. As the price of the car goes f
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4 0
3 years ago
In Canada in 1998 the estimated number of households that owned 2 or more vehicles was 3.939 x 10 6
WITCHER [35]

In Canada in 1998 the estimated number of households written in standard decimal notation is 3939000

<u>Solution:</u>

Given that in 1998 estimated number of households that owned 2 or more vehicles was 3.939 \times 10^{6}

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In this case we need to move the decimal point based on the power of 10.

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Let’s first take a number without 10^6 and add six zeros on right.

So we get 3.939000000

Now multiplying above number by 10^6 means moving the decimal after 6 numbers from the current position, that means  

3.939 \times 10^{6}=3939000.00

That is 3939000 is required standard decimal notation of scientific notation number 3.939 \times 10^{6}

5 0
3 years ago
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