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3 years ago

Choose all of the equations for which x = 2 is a solution.

Mathematics

2 answers:

OlgaM077 [116]3 years ago

8 0

A & E (mark brainliest if right pls)

PSYCHO15rus [73]3 years ago

3 0

A and D.

EXPLANATION
x + 3 = 5
2+3=5
x - 2 = 4
2-2=4
hopes this helps :)

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HELP I DONT GET #10! PLZ HELP!

zhenek [66]

Yes, there will be more than 100 inches because there are 12 inches in a foot so it’s 100x12 which means it’s going to be 1,200 inches per second

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3 years ago

Michael has $1,059.35 in his checking account. He is going to spend $466.43 on a new television, and he will spend the rest on s

sesenic [268]

Answer:

D. $43.00x + $466.43 < $1,059.35

Step-by-step explanation:

He has $1,059.35.

The amount of speakers he buys is x.

Each speaker is $43.00, and he is buying one television, which is $466.43.

All of the speakers he buys and(+) the television must be less than $1,059.35 because that's all he has. It cannot be more, which is why the equation is $43.00x + $466.43 < $1,059.35.

Hope this helps!

3 0

2 years ago

Read 2 more answers

If a and b are positive numbers, find the maximum value of f(x) = x^a(2 − x)^b on the interval 0 ≤ x ≤ 2.

Ad libitum [116K]

Answer:

The maximum value of f(x) occurs at:

$\displaystyle x = \frac{2a}{a+b}$

And is given by:

$\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b$

Step-by-step explanation:

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle f(x) = x^a (2-x)^b \text{ where } a, b >0$

And we want to find the maximum value of f(x) on the interval [0, 2].

First, let's evaluate the endpoints of the interval:

$\displaystyle f(0) = (0)^a(2-(0))^b = 0$

And:

$\displaystyle f(2) = (2)^a(2-(2))^b = 0$

Recall that extrema occurs at a function's critical points. The critical points of a function at the points where its derivative is either zero or undefined. Thus, find the derivative of the function:

$\displaystyle f'(x) = \frac{d}{dx} \left[ x^a\left(2-x\right)^b\right]$

By the Product Rule:

$\displaystyle \begin{aligned} f'(x) &= \frac{d}{dx}\left[x^a\right] (2-x)^b + x^a\frac{d}{dx}\left[(2-x)^b\right]\\ \\ &=\left(ax^{a-1}\right)\left(2-x\right)^b + x^a\left(b(2-x)^{b-1}\cdot -1\right) \\ \\ &= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right] \end{aligned}$

Set the derivative equal to zero and solve for x:

$\displaystyle 0= x^a\left(2-x\right)^b \left[\frac{a}{x} - \frac{b}{2-x}\right]$

By the Zero Product Property:

$\displaystyle x^a (2-x)^b = 0\text{ or } \frac{a}{x} - \frac{b}{2-x} = 0$

The solutions to the first equation are x = 0 and x = 2.

First, for the second equation, note that it is undefined when x = 0 and x = 2.

To solve for x, we can multiply both sides by the denominators.

$\displaystyle\left( \frac{a}{x} - \frac{b}{2-x} \right)\left((x(2-x)\right) = 0(x(2-x))$

Simplify:

$\displaystyle a(2-x) - b(x) = 0$

And solve for x:

$\displaystyle \begin{aligned} 2a-ax-bx &= 0 \\ 2a &= ax+bx \\ 2a&= x(a+b) \\ \frac{2a}{a+b} &= x \end{aligned}$

So, our critical points are:

$\displaystyle x = 0 , 2 , \text{ and } \frac{2a}{a+b}$

We already know that f(0) = f(2) = 0.

For the third point, we can see that:

$\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(2- \frac{2a}{a+b}\right)^b$

This can be simplified to:

$\displaystyle f\left(\frac{2a}{a+b}\right) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b$

Since a and b > 0, both factors must be positive. Thus, f(2a / (a + b)) > 0. So, this must be the maximum value.

To confirm that this is indeed a maximum, we can select values to test. Let a = 2 and b = 3. Then:

$\displaystyle f'(x) = x^2(2-x)^3\left(\frac{2}{x} - \frac{3}{2-x}\right)$

The critical point will be at:

$\displaystyle x= \frac{2(2)}{(2)+(3)} = \frac{4}{5}=0.8$

Testing x = 0.5 and x = 1 yields that:

$\displaystyle f'(0.5) >0\text{ and } f'(1)$

Since the derivative is positive and then negative, we can conclude that the point is indeed a maximum.

Therefore, the maximum value of f(x) occurs at:

$\displaystyle x = \frac{2a}{a+b}$

And is given by:

$\displaystyle f_{\text{max}}(x) = \left(\frac{2a}{a+b}\right)^a\left(\frac{2b}{a+b}\right)^b$

5 0

3 years ago

Sum of 15, - 2 and 7 is

ioda

Answer:

<h2>done please mark me brainliest and follow me lots of love from my heart and soul Darling TEJASWINI SINHA HERE ❤️</h2>

Step-by-step explanation:

Solution: 15/2 = 7.5

7/2 = 3.5

The smaller number = 7.5-3.5 or 4, and the larger number is 7.5+3.5 or 11. Answer.

4 0

3 years ago

13. Connie wants to paint one wall in her living room. Along the wall, she

erica [24]

Answer: Approximately 96 square feet

======================================================

Work Shown:

1 ft = 30 cm

1 ft = (5*6) cm

1 ft = 5*(6 cm)

1 ft = 5*(1 board width)

1 ft = 5 board widths

12*(1 ft) = 12*(5 board widths)

12 ft = 60 board widths

12 ft = 1 full wall length

The wall is 12 feet horizontally across and 8 feet tall, so its estimated area is 12*8 = 96 square feet approximately. This is approximate because of the fact we used the approximation of 1 ft = 30 cm.

7 0

3 years ago