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inessss [21]
3 years ago
11

Does anybody know the answer please.

Mathematics
2 answers:
wariber [46]3 years ago
8 0

Answer:

The sign of each y-coordinate changed.

Step-by-step explanation:

This was a reflection over the x-axis.

If you look at point F, it is (-5, -1) the corresponding point F' is (-5,1).  Notice the numerical values of x and y are the same, but the sign of y flipped from negative to positive. The other four points all follow the same pattern.

VARVARA [1.3K]3 years ago
8 0
That person is correct ^^
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Fill in the blank to complete the equation below.<br> 33 +?= 3(11 + 8)
svetlana [45]

Answer:

24

Step-by-step explanation:

11+8=19

19×3=57

33-54=24

3 0
2 years ago
Read 2 more answers
A gym charges a $40 registration fee and $25 per month of membership. Create an equation to model the price (y) based on (x) mon
Lubov Fominskaja [6]

Answer:

y= 40 + 25x

Hope this helps!

8 0
3 years ago
I need to solve these two equations using either substitution or elimination
vitfil [10]

Answer:

y = -15

x = -10

Step-by-step explanation:

1/4x - 1/2 = 5 (1)

3x + 2/3y = -40 (2)

Multiply (1) by 4

1/4x - 1/2 = 5

1/4x * 4 - 1/2y * 4 = 5 * 4

4/4x - 4/2y = 20

x - 2y = 20 (3)

Multiply (2) by 3

3x + 2/3y = -40 (2)

3x * 3 + 2/3y * 3 = -40 * 3

9x + 6/3y = -120

9x + 2y = -120 (4)

x - 2y = 20 (3)

9x + 2y = -120 (4)

Using elimination method, Add (3) and (4)

9x + x = -120 + 20

10x = -100

x = -100/10

x = -10

Substitute x = -10 into (3)

x - 2y = 20 (3)

-10 - 2y = 20

-2y = 20 + 10

-2y = 30

y = 30/-2

y = -15

y = -15

x = -10

8 0
3 years ago
Find the area enclosed between f(x)=0.3x2+7 and g(x)=x from x=−4 to x=8.
denis23 [38]
First, we sketch a picture to get a sense of the problem. g(x)=x is a diagonal line through (0,0) with slope = = 1. Since we are interested in the area between x = -4 and x = 8, we find the points on the line at these values. These are (-4, -4) and (8,8).

f(x) is a parabola. It's lowest point occurs when x = 0. It is the point (0,7). At x = -4 and x=8 it has the values 11.8 and 26.2 respectively. That is, it contains the points (-4, 11.8) and (8,26.2).

From these we make a rough sketch (see attachment). This is a sketch and mine is very incorrect when it comes to scale but what matters here is which of the curves is on top, which is below and whether they intersect anywhere in the interval, so my rough sketch is good enough. From the sketch we see that f(x) is always above (greater than) g(x).

To find the area between the curves over the given interval we integrate their difference and since f(x) is strictly greater than g(x) we subtract as follows: f(x) - g(x). The limits of integration are the values -4 and 8 (the x-values between which we are looking for the area.

Now let's integrate:
\int\limits^{8}_ {-4}f(x)-g(x) \, dx = \int\limits^{8}_ {-4}.3 x^{2} +7-x \, dx
The integral yields: [tex](\frac{.3 (8)^{3} }{3} +7(8)- \frac{ (8)^{2} }{2}) -(\frac{.3 (-4)^{3} }{3} +7(-4)- \frac{ (-4)^{2} }{2}) = 117.6 [/tex]
We evaluate this for 8 and for -4 subtracting the second FROM the first to get:


4 0
3 years ago
Can you guys help me with this
Nonamiya [84]

The measure of angle C is 60 degrees. All the angles have to equal 180 degrees when added together. Since there is one right angle, 90 degrees, and one 30 degree angle, the last angle can only equal 60 degrees.

5 0
3 years ago
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