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Free_Kalibri [48]
3 years ago
6

(20 points)

Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Step-by-step explanation:

I want to say B) 130 but not 100% sure. Sorry if my answer is wrong.

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Please help stuck on question
vazorg [7]

Answer:

Suppose we have a polynomial of degree N with a leading coefficient A and roots {x₁, x₂, ..., xₙ}

We can write this polynomial as:

P(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

such that the terms:

(x - x₁), (x - x₂), etc...

are called the factors.

In this case, we know that the roots OF THE FACTORS

are:

(x = - 2)

(x = - (1 + √5))

(x = + 3i)

If the root of the polynomial is  x = -2, then the factor should be:

(x + 2)

which is zero when we evaluate x in -2

Then the correct option is the first one.

5 0
3 years ago
Find the slope x intercept and y intercept of the line y equals 2x + 1​
Ad libitum [116K]

(i) Slope is m=2

(ii) x - intercept is \left(-\frac{1}{2}, 0\right)

(ii) y - intercept is (0,1)

Explanation:

The given equation is y=2x+1

We need to determine the slope, x - intercept and the y - intercept

(i) Let us determine the slope of the equation.

Since, the equation is of the form y=mx+b where m is the slope

Thus, comparing the equation y=2x+1 with the general form y=mx+b, the slope is 2.

Thus, slope is m=2

(ii) Now, we shall determine the x - intercepts.

The x - intercept can be determined by substituting y=0 in y=2x+1

Thus, we have,

  0=2x+1

-1=2x

\frac{-1}{2} =x

Thus, the x - intercept is \left(-\frac{1}{2}, 0\right)

(iii) The y - intercept can be determined by substituting x=0 in y=2x+1

Thus, we get,

y=2(0)+1

y=0+1

y=1

Thus, the y - intercept is (0,1)

6 0
3 years ago
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