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rosijanka [135]
3 years ago
5

Explain one significant economic or political cause for the outbreak of the French Revolution in 1789.

Advanced Placement (AP)
1 answer:
sergeinik [125]3 years ago
3 0

The correct answer to this open question is the following.

One significant economic cause for the outbreak of the French Revolution in 1789 was the hunger and poverty in a time when the King of France and his court lived an opulent life.

Yes, the economic issues that led the French people to revolt against their government were that hunger and poverty in a time when the King of France and his court lived an opulent life.

This created and injustice and equality because the third state members were the ones who had to pay most of the taxes, making the king richer while they were very poor.

The harsh economic conditions lived by the members of teh Third State and the inequity and injustice, were issues that made the French people start the revolt.

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\bold{\huge{\pink{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>given </u><u>one </u><u>irregular </u><u>figure </u><u>which </u><u>is </u><u>composed </u><u>2</u><u> </u><u>triangle's </u><u>and </u><u>3</u><u> </u><u>rectangles </u>
  • <u>The </u><u>height </u><u>and </u><u>base </u><u>of </u><u>the </u><u>triangles</u><u> </u><u>is </u><u>6cm </u><u>and </u><u>7</u><u> </u><u>cm</u><u> </u><u>each </u>
  • <u>The </u><u>length </u><u>and </u><u>breath </u><u>of </u><u>the </u><u>rectangles</u><u> </u><u>is </u><u>1</u><u>3</u><u>.</u><u>1</u><u> </u><u>cm </u><u>and </u><u>7cm </u><u>each </u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>total </u><u>surface </u><u>area </u><u>of </u><u>the </u><u>given </u><u>figure</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

  • 2 triangles of height 6 cm and base 7cm each
  • 3 rectangles of length 13.1 cm and 7cm each

<u>Therefore</u><u> </u><u>,</u>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of triangle

\bold{=}{\bold{\pink{\dfrac{1}{2}}}}{\bold{\pink{ × Base × Height }}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

<u>Area </u><u>of </u><u>1</u><u> </u><u>triangle </u>

\sf{=}{\sf{\dfrac{1}{2}}}{\sf{ × 7 × 6 }}

\sf{ = 7 × 3 }

\sf{ = 21 cm²}

<h3><u>Therefore</u><u>, </u></h3>

<u>Area </u><u>of </u><u>2</u><u> </u><u>triangle's </u>

\sf{ = 2 × ( Area\:of\:1\:traingle) }

\sf{ = 2 × 21 }

\sf{ = 42 cm² }

Thus, The area of 2 triangles is 42 cm²

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of rectangle

\bold{\red{ = Length × Breath }}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of 1 rectangle

\sf{ = 13.1 × 7 }

\sf{ = 91.7 cm² }

<h3><u>Therefore</u><u>,</u></h3>

<u>Area </u><u>of </u><u>3</u><u> </u><u>rectangles </u>

\sf{ = 3 ×( Area\:of\:1\:rectangle)  }

\sf{ = 3 × 91.7 }

\sf{ = 275.1 cm² }

Thus, The area of 3 rectangle is 275.1 cm²

<h3><u>So</u><u>, </u></h3>

Total area of the given figure

  • = Area of 2 triangles + Area of 3 rectangles

\sf{ = 42 + 275.1 }

\bold{ = 317.1 cm²}

Hence, The total surface area of the given figure is 317.1 cm² .

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