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3 years ago

Help? which one should I choose

Mathematics

1 answer:

Gelneren [198K]3 years ago

8 0

Answer:

Step-by-step explanation:

12 is the value of x because 2x-12 is within x so i times it so i got the answer

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Javier By 48 cards at a yard sale. Of the cards 3/8 were basketball cards how many cards were baseball card

Hatshy [7]

The answer is 18, Hope you get it right!

3 0

3 years ago

Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3

k0ka [10]

Answer:

x = $\frac{3}{2}$

Step-by-step explanation:

Given

f(x) = $\frac{x-4}{2x-3}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

Thus x = $\frac{3}{2}$ is the vertical asymptote

5 0

4 years ago

Sabrina reads 15 pages per hour. She needs to finish a book with 120 pages. Which equation would you use to determine how many h

frozen [14]

Answer:

15x=120

Step-by-step explanation:

8 0

3 years ago

Find the values of a and b such that x2 - 2x + 2 = (x -a) + b LOADS OF POINTS ON THE LINE!!!

Hitman42 [59]

Answer:

Step-by-step explanation:

Factorize using square root method.

x² - 2x + 2 = (x-a)² + b

x² -2x + 1 + 1 = (x-a)²+b

(x² - 2*x*1 + 1²) + 1 = (x -a)²+ b {Compare with a²- 2ab+b² which is (a - b)²}

(x - 1)² + 1 = (x - a)² + b

a = 1 and b = 1

6 0

3 years ago

The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

4 years ago