Answer:
Let's talk through this a one step at a time.
*Since f(x) is concave-up with its vertex on the x-axis, we know f(x) ≥ 0.
*We also know that when we shift a function's domain by a positive number, we shift the function left and when we shift a function's domain by a negative number, we shift the function right. So f(x-5) is f(x) shifted to the right by 5.
*At this point, f(x-5) has its vertex at (5,0).
*When we negate f(x-5), the parabola becomes concave down yet the vertex remains at (5,0). Now we're at -f(x-5). At this point we have -f(x-5)≤0 with a range (-∞,0]
*If we add 2 to create g(x)=2-f(x-5), then we have a concave down parabola with its vertex shifted up by 2, at (5,2). So, g(x) is concave down with its vertex at (5,2). Hence
Answer:
3p² + 32p + 13
Step-by-step explanation:
Okay, so lets first solve for 2b. 2b = 2(p + 5), which is equal to 2p + 10. Now, let's solve for 3a. 3a = 3(p² + 10p +1), simplifying to 3p² + 30p +3. After adding 2b and 3a, we are able to get 2p + 10 + 3p² + 30p + 3 = 3p² + 32p + 13
Answer:
Then answer will still be the same, unless you have a number for a and x to multiply it
Step-by-step explanation:
To solve this you want to plug in your x's and y's to see if they match.
A. 3(11)-4=33-4=29 and 29 is not equal to 5 so A is not a solution
B.3(5)-4=15-4=11=11 3(3)-4=9-4=5 and 5 is not equal to 2 so B is not a solution
C. 3(2)-4= 6-4=2 2 is not equal to 3 so C is not a solution
D is the answer. 3(5)-4=11 and 3(2)-4= 2
Brian (I think you meant Brian haha..) is incorrect because the tenth place is the number right after the decimal which is a 4. If you are rounding to the tenth place that means that you have to look at the number to the right of that, which is 4. 5 and up means you round up and 4 and down means you round down. This is a 4, so you keep the 4 after the decimal and get rid of the last 4. Therefore, when rounded it would be: 4.4.
Hope this helped! Good luck! :)
