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Firlakuza [10]
3 years ago
10

What would happen if a proton were added to the nucleus of the atom? (Check all

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

A. It would become a different atom.

C. Its charge would increase by 1

Step-by-step explanation:

Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

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Shelly and Terrence completed a different number of tasks in a game. Shelly earned 90 points on each task. Terrence's total poin
fgiga [73]
I'm thinking maybe x is supposed to represent the number of tasks completed because it states Shelly earned 90 points on each task.  Then when put together it may look like this, let's say there are 4 tasks= Ex.90 times the 4 tasks minus 20 points which would total the points Terrence's has earned. So i believe x is the total tasks. Hope I didn't make it confusing...
6 0
3 years ago
Read 2 more answers
Number of Certified Organic Farms in the United States, 2001–2008
Vinil7 [7]

Answer:

ŷ = 739.49X + 4876.43

y = 6755.98 - 388.24x + 125.30x²

y = 5428.98(1.09)^x

B.)

Linear:

ŷ = 739.49(9) + 4876.43

y = 11531.8

Year 2010 ; x = 10

y = 739.49(10) + 4876.43

y = 12271.3

Year 2011 ; x = 11

y = 739.49(11) + 4876.43

y = 13010.8

Quadratic :

Year 2009 ; x = 9

y = 6755.98 - 388.24(9) + 125.30(9^2)

y = 13411.1

Year 2010 ; x = 10

y = 6755.98 - 388.24(10) + 125.30(10^2)

y = 15403.6

Year 2011 ; x = 11

y = 6755.98 - 388.24(11) + 125.30(11^2)

y = 17646.6

Exponential:

Year 2009 ; x = 9

y = 5428.98(1.09)^9

y = 11791.2

Year 2010 ; x = 10

y = 5428.98(1.09)^10

y = 12852.4

Year 2011 ; x = 11

y = 5428.98(1.09)^11

y = 14009.1

Step-by-step explanation:

X :

1

2

3

4

5

6

7

8

Y:

6231

6574

7237

7211

7701

8581

10302

11796

Using the online linear regression calculator :

The linear trend :

ŷ = 739.49X + 4876.43

Where x = year

With 2006 representing 1 ; and so on

Slope = m = 739.49

Intercept (c) = 4876.43

y = predicted variable

The quadratic model:

General form:

y = A + Bx + Cx²

y = 6755.98 - 388.24x + 125.30x²

The exponential model:

y = AB^x

y = 5428.98(1.09)^x

B.) Next three years :

Year 2009 ; x = 9

Year 2010 ; x = 10

Year 2011 ; x = 11

Linear:

ŷ = 739.49(9) + 4876.43

y = 11531.8

Year 2010 ; x = 10

y = 739.49(10) + 4876.43

y = 12271.3

Year 2011 ; x = 11

y = 739.49(11) + 4876.43

y = 13010.8

Quadratic :

Year 2009 ; x = 9

y = 6755.98 - 388.24(9) + 125.30(9^2)

y = 13411.1

Year 2010 ; x = 10

y = 6755.98 - 388.24(10) + 125.30(10^2)

y = 15403.6

Year 2011 ; x = 11

y = 6755.98 - 388.24(11) + 125.30(11^2)

y = 17646.6

Exponential:

Year 2009 ; x = 9

y = 5428.98(1.09)^9

y = 11791.2

Year 2010 ; x = 10

y = 5428.98(1.09)^10

y = 12852.4

Year 2011 ; x = 11

y = 5428.98(1.09)^11

y = 14009.1

6 0
2 years ago
Please Help!!!!!!!<br> Simplify (√5)(3√5).
kirill [66]

The answer is 15

multiply 3sqrt(25)

3*5=15

7 0
3 years ago
I am struggling could someone please help me.
ryzh [129]

Answer:

- 30 cud be the answer for the question, I'm not really sure

6 0
2 years ago
Which answer is correct ? Please explain why !!
Arturiano [62]
C because there are 10 cents in a dime, and 5 cents in a nickel
3 0
3 years ago
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