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Firlakuza [10]
3 years ago
10

What would happen if a proton were added to the nucleus of the atom? (Check all

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

A. It would become a different atom.

C. Its charge would increase by 1

Step-by-step explanation:

Adding or removing protons from the nucleus changes the charge of the nucleus and changes that atom's atomic number. So, adding or removing protons from the nucleus changes what element that atom is! For example, adding a proton to the nucleus of an atom of hydrogen creates an atom of helium.

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Find the area of a circle with a diameter of four
Elis [28]

Answer:

12.57

Step-by-step explanation:

the formula for the area of a circle is \pi r^{2}

the diameter is 2 times the radius, so dividing it by 2 gives you a radius of 2

substitute the 2 for the r in the formula and solve

\pi 2^{2}

4\pi

≈12.57

7 0
3 years ago
Read 2 more answers
A circle with area 16pi has a sector with a central angle of 8/5pi radians. What is the area of the sector?
lianna [129]

Answer:

The area of the sector is 12.8\pi\ units^2

Step-by-step explanation:

we know that

The area of a complete circle (16π units^2) subtends a central angle of 2π radians

so

using proportion

Find out the area of a sector , if the central angle is equal to 8π/5 radians

\frac{16\pi}{2\pi}=\frac{x}{(8\pi/5)}\\\\x=8(8\pi/5)\\\\x= 12.8\pi\ units^2

4 0
3 years ago
Read 2 more answers
.A bag contains 3 red checkers and 5 black checkers. A checker is selected, kept out of the bag, and then another checker is sel
cupoosta [38]

Answer: 15 / 56

Step-by-step explanation:

Number of red checkers = 3

Number of black checkers = 5

Total number of checkers = 8

P(black, then red) = 5/8 × 3/7 = 15/56

We should note that the probability to pick a black checker first will be 5 out of 8. Then, there'll be 7 checkers left and the probability to pick a res checker will be 3/7. We then multiply the probabality of each together.

5 0
2 years ago
What is the square root of four
Elina [12.6K]

Answer:

The square root of 4 is 2

Step-by-step explanation:

8 0
3 years ago
The diagonals of rhombus fghj intersect at point k. if side gh is equal to 3x - 10 and side jh is equal to 6x - 19, find x
exis [7]
A rhombus is a square but turned so it looks like a diamond. This means all the sides are equal. With this information we can build an equation to solve for x.

3x - 10 = 6x - 19

1) Subtract 3x from both sides.

-10 = 3x - 19

2) Add 19 to both sides.

9 = 3x

3) Divide both sides by 3.

3 = x

x =3.
8 0
3 years ago
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