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natta225 [31]
3 years ago
8

What is the area of the figure below? 40 mm2 80 mm2 88 mm2 96 mm2

Mathematics
2 answers:
frez [133]3 years ago
8 0
88 mm2 that the answer
Anvisha [2.4K]3 years ago
6 0
The answer for this question is 88mm2
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A hair salon receives a shipment of 84 bottles of hair conditioner to use and sell to customers. The two types are labels type A
Rom4ik [11]
x-\ botlle\ A\\y-\ bottle\ B\\\\ \left \{ {{x+y=84} \atop {6,5x+8,25y=588}} \right. \\\\ \left \{ {{x=84-y} \atop {6,5x+8,25y=588}} \right. \\\\Substitution\ method\\\\
6,5(84-y)+8,25y=588\\\\
546-6,5y+8,25y=588\ \ \ | subtract\ 546
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6 0
3 years ago
A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and
Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

<h3>How to determine the equation</h3>

The equation is a secant function represented by

y =A\sec(Bt)

Where:

A represents the amplitude

So, we have:

A = 40 --- the distance of the light from each square wall

B represents the period, and it is calculated as:

B = \frac{2\pi}{T}

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

B = \frac{2\pi}{6}

Simplify

B = \frac{\pi}{3}

Substitute values for A and B in y =A\sec(Bt)

y = 40\sec(\frac{\pi}{3}t)

Rewrite as a function

d(t) = 40\sec(\frac{\pi}{3}t)

Hence, the equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0
2 years ago
Lucy's fish tank has 14 liters of water in it. She plans to add 5 liters per minute until the tank has at least 49 liters. What
Vikentia [17]

Answer:

Step-by-step explanation:

14 + 5t > = 49 (thats a greater then or equal sign)

5t > = 49 - 14

5t > = 35

t > = 35/5

t > = 7 <===

3 0
3 years ago
For the rational expression 2x^2-7x-15/x^2-25, do both of the following,
Mrrafil [7]

Answer:

a. \frac{2x + 3}{x+5}

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

2x^2 - 7x - 15              

Two numbers that multiply to -30 and add to -7 = -3 and 10

[2x^2 - 10x] + [3x - 15]

(2x + 3)(x - 5)

Factor the denominator (Difference of Two Squares):

x^2 - 25 = (x +5)(x-5)

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}

Variable Restrictions:

Denominator ≠ 0

x + 5 = 0\\x = -5

Vertical asymptote at x = -5 ⇒ x ≠ -5

3 0
3 years ago
Please help with solving the blank answers
KATRIN_1 [288]
Distribute The 4 In Problem Number 2. (4*2.5X)+(4*1.25) = 77
Simplify. 10X+5 = 77. Now, Subtract 5 From Both Sides. 
10X = 77-5
10X = 72.
Now, Divide.
X = 72/10. 
X = 7.2.
For 13, We Have This:
3/5p+2/3 = 8.
Now, Subtract 2/3. 
3/5p = 7 1/3
Now, Divide. 
7 1/3 Needs To Be Converted To An Improper Fraction. 
It Becomes 22/3.
22    5    110
--- * --- = ----
 3     3      9
Now, Make Into A Proper Fraction.
It Becomes 12 And 2/9. 

6 0
3 years ago
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