The zeros of a quadratic function are found where the graph intersects the x-axis. If the graph interects the x-axis in 2 places, we have 2 real solutions; if the graph intersects--or just touches--the x-axis in one place we have one real solution multiplicity 2; if the graph doesn't go through the x-axis at all we have 2 imaginary solutions. Ours goes through the x-axis in 2 places so we have 2 real solutions. Choice A.
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8+4p+2q+r=0
27+9p+3q+r=0
64+16p+4q+r=0
P=-9
Q=26
R=-24
Answer:
D
Step-by-step explanation:
Answer: Statement p is false.
Step-by-step explanation:
In both cases, we need to isolate the variables:
p: -3*x + 8*x - 5*x = x
(-3*x - 5*x) + 8*x = x
-8x + 8*x = x
0 = x
This will be true only for one value of x, so this is not always true, which means that the statement is false.
q: (3*x)*(5*y) = 15*x*y
let's solve the left side:
3*x*5*y = 15*x*y
(3*5)*(x*y) = 15*x*y
15*x*y = 15*x*y
This is true for every value of x and y, then this statement is true.
