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belka [17]
3 years ago
6

A ship at sea is 70 miles from one radio transmitter and 130 miles from another. The bearing from the ship to transmitter 1 is N

38.1°E and the bearing to transmitter 2 is S 22.4°E . Find the distance between the two transmitters. ​
Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

volved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.

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I can’t seem to find this, I’m having trouble with this question! It would be nice if someone could help! Thanks
Elenna [48]

Answer:

-456 I think but I could be wrong though

8 0
2 years ago
Which estimate is closest to the actual value of (2.99548)⋅(1.8342)?
inn [45]

estimate value of :- 2.99548 is 3

estimate value of :- 1.8342 is 2

So 3•2=6

so 6 is your answer

4 0
2 years ago
Read 2 more answers
Pls help I don’t get it
nirvana33 [79]

Well you are trying to find x, so you would divide 5/8 by itself and on the other side.

(5/8x / 5/8) = (10 / 5/8)

x=16

Hope this helps!

8 0
3 years ago
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How do you subtract 42 minutes from 1 hour 25 minutes? explain what to do and why to do it.
ikadub [295]

Answer:

43

Step-by-step explanation:

you change the 1 hour into minute you and 60min to 25 minutes and then you subtract from 42 minutes to get the solution

8 0
3 years ago
The area of a rectangle is 44m. The height is 11/3m. What is the length?
iogann1982 [59]

Width of the rectangle is 12m

<u>Explanation:</u>

<u></u>

Area of rectangle = 44m

height = \frac{11}{3}m

area of rectangle = length X breadth

44 = \frac{11}{3} X b\\b = 12m

Therefore, width of the rectangle is 12m

4 0
3 years ago
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