Problem 1.
Think of the outer rectangle by joining the two 5 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 28 in.
The left and right sides measure 5 in. + 12 in. + 5 in. = 22 in.
Area of the outer rectangle = LW = 28 in. * 22 in. = 616 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
area of white rectangle = LW = 12 in. * 15 in. = 180 in.^2
Subtract the areas:
616 in.^2 - 180 in.^2 = 436 in.^2
Answer:
<span>A. 436 Square Inches
Problem 2.
Do the same thing as for problem 1. Join the two 4 in. segments with a line.
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<span>Think of the outer rectangle by joining the two 4 in. sides with a segment.
Now you have an outer blue rectangle with a white rectangle missing.
For the outer rectangle:
The top and bottom sides measure 24 in.
The left and right sides measure 4 in. + 12 in. + 4 in. = 20 in.
Area of the outer rectangle = LW = 24 in. * 20 in. = 480 in.^2
Now look at the white square. You need to subtract this area from the outer rectangle.
area of white rectangle = LW = 12 in. * 13 in. = 156 in.^2
Subtract the areas:
480 in.^2 - 156 in.^2 = 324 in.^2
Answer:
</span><span>B. 324 Square Inches</span>
Binomial theory : ( a - b ) ^3 = a^3 - 3a^2b + 3ab^2 - b^3 ;
Then, ( 2y - 3x ) ^3 = 8y^3 - 36y^2x + 54yx^2 - 27x^3
<em>km</em>=<em>x, </em>the product being represented by <em>x.
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Answer:
(a.) It passes through the point (3,-6) and is parallel to the line 3x + y - 10 = 0.
(b). It has x-intercept 6 and y-intercept 4.
Step-by-step explanation:
Answer:
y=4x/5+5
Step-by-step explanation:
Points are (0,5) and (-5,1)
(y-5)/(1-5)=x-0/[0-(-5)]
(y-5)/4=x/5
*5/5 *4/4
5(y-5)/20=4x/20
5y-25=4x
+25 +25
5y=4x+25
:5 :5
y=4/5*x+5