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harkovskaia [24]
3 years ago
8

Michael spent $18 at a local farmers’ market. The apples he bought cost $2 per pound, and the peppers cost $3 per pound. How man

y pounds of apples and peppers did he buy?
This equation represents the scenario:

2a + 3p = 18

Choose the equations that are equivalent.
Check all that apply.
p = two-thirds a + 6
p = negative two-thirds a + 6
a = negative 1 and one-half p + 9
a = 1 and one-half p + 9
a = StartFraction negative 3 p + 18 Over 2 EndFraction
Mathematics
2 answers:
VashaNatasha [74]3 years ago
6 0

Answer:

p=-2/3a + 6

a=-1 1/2p + 9

a= -3p+18/2

velikii [3]3 years ago
3 0

Answer:

B C and E

Step-by-step explanation:

got it right on edge after clicking A instead of B

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A psychology class consists of 14 males and 36 females. if the professor selects name from the class list using random sampling,
Pavel [41]
The total number of students is 14+36, or 50. So the chance that a selected student is female is 36/50, or 18/25.
3 0
3 years ago
Business Loss A company loses $144 as a result of a shipping delay. The 9 owners of the
koban [17]

Answer:

Each person will earn $16.

Step-by-step explanation:

Given that:

Amount of loss faced by the company = $144

Number of people who would share the amount = 9

Let,

x be the share of each person.

Number of people * Share per person = Total loss

9x = 144

Dividing both sides by 9

\frac{9x}{9}=\frac{144}{9}\\

x = $16

Hence,

Each person will earn $16.

5 0
3 years ago
How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

\cos\left(\dfrac{7\pi}5(t+20)\right)=\cos\dfrac{7\pi t}5\underbrace{\cos28\pi}_1-\sin\dfrac{7\pi t}5\underbrace{\sin28\pi}_0=\cos\dfrac{7\pi t}5

More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
4 0
3 years ago
Explain how solving 8+2 can help you solve 80+20.
katrin [286]
Becuase 80 is the same as 8 but has an extra 0 at the end (which makes it 80) and same for 20 to 2. 8 + 2 = 10 (now add a zero at the end). The answer should be 100.
5 0
3 years ago
Read 2 more answers
The number 6458 rounded to the nearest thousand
Murrr4er [49]

Answer:

6500

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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