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3 years ago

A triangle has legs of 5cm and 6cm. How long is its hypotenuse? Round to the nearest tenth!

2 answers:

7 0

To solve this you use the pythagorean’s theorem which states that a^2 plus b^2 = c^2.
c being the hypotenuse
and a and b being the legs of the triangle
so in this example a is 5 and b is 6
so we ca. plug it in to the equation and we get : 5^2 plus 6^2 equals c^2
which further simplifies to 25 plus 36 = c^2
then add 25 and 36:
61 = c^2
then find the square root of both sides to get the variable (c) alone
square root of 61 = square root of c
which is 7.81 = c
that’s in decimal form
however since it’s says round to the tenth we can round the answer to get 7.8
therefore your final answer is 7.8
the hypotenuse is 7.8
hope this helped!
let me know if you have any questions

Leno4ka [110]3 years ago

4 0

Answer:

I KNOW YOU ARE POKEMMON GO GIVE ME VBUX KID 1V1 ME

Step-by-step explanation:

YOU WONT KID

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3 years ago

Read 2 more answers

How much longer is the hypotenuse of the triangle than its shorter leg?

RUDIKE [14]

This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

d. 10 ft

Answer : The correct option is, (b) 4 ft

Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(AB)^2=(AC)^2+(BC)^2$

Given:

Side AC = 6 ft

Side BC = 8 ft

Now put all the values in the above expression, we get the value of side AB.

$(AB)^2=(6)^2+(8)^2$

$AB=\sqrt{(6)^2+(8)^2}$

$AB=10ft$

Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.

Difference = Side AB - Side AC

Difference = 10 ft - 6 ft

Difference = 4 ft

Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.

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