Answer:
A(x) = (24 -2x)√(6(x -6))
Step-by-step explanation:
Heron's formula for the area of a triangle in terms of sides a, b, and c is ...
A = √(s(s -a)(s -b)(s -c))
where s is the semi-perimeter.
Here, we have s = 24/2 = 12, and a = b = x, c = 24-2x. So, the area is ...
A = √(12(12 -x)(12 -x)(12 -(24 -2x)) = (12 -x)√(12(2x -12))
A = 2(12 -x)√(6(x -6))
OOHHH!! I like sci not! Okay, so you take the decimal ( which in this case is at the end: 68000. ) and move it over as many times as needed until it gets in between the, in this case, 6 and 8. ( 6.8000 ). You need to show exactly how many times it was actually moved so you multiply that number time 10^ whatever place. In this question, it'll be to the 4th place because you move the decimal over 4 times. The answer will be 6.80 x 10^4 OR -written in short hand- 6.8x10E4
Answer:
option C is correct answer ..
Step-by-step explanation:
angle A + angle B + angle C = 180° ( by angle sum property of triangle )
3x + 4x-19+ 3x -1 = 180
10x + -20 = 180
10x = 180 +20 = 200
x = 200/10 = 20 °
angle A = 3× 20 = 60 °
angle B = 4× 20 - 1 9 = 61 °
angle C = 3× 20 -1 = 59 °
angle B is greatest so side opposite to it will be greatest in length ....so length of AC is greatest ....
so option C is the correct answer of this question ...
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Answer:
- g(- x) = - 70 - 3x
Step-by-step explanation:
to evaluate g(- x) substitute x = - x into g(x)
g(- x) = 70 - 3(- x) = 70 + 3x, hence
- g(- x) = - (70 + 3x) = - 70 - 3x
Answer:
5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2)
Step-by-step explanation:
In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:
x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)
x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)
Now that you have factored out the two quadratics, plug them into the equation.
5x - 3
(x+4)(x+2) (x+5)(x+2)
Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.
5x (x+5) - 3(x+4)
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:
5x^2+25x - (3x+12) = 5x^2+22x-12 x cannot be -5, -4, -2
(x+5)(x+4)(x+2) (x+5)(x+4)(x+2)
