Answer:
7
Step-by-step explanation:
(a+b)/2 x h
42 = (8+4)/2 x h
42 = 6h
h = 7
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+ ![\frac{-2x}{-7}](https://tex.z-dn.net/?f=%5Cfrac%7B-2x%7D%7B-7%7D)
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)
Answer:
![\huge\boxed{[-5;\ -2)\ \cup\ [3;\ 13)}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5B-5%3B%5C%20-2%29%5C%20%5Ccup%5C%20%5B3%3B%5C%2013%29%7D)
Step-by-step explanation:
The following piecewise functions are linear functions. The graph of any of them is a line segment.
We just need to calculate the value of the function at each end specified in the brace.
![y=3x-2\ \text{if}\ -1\leq x](https://tex.z-dn.net/?f=y%3D3x-2%5C%20%5Ctext%7Bif%7D%5C%20-1%5Cleq%20x%3C0)
Substitute x =-1 and x = 0:
![x=-1\\y=3(-1)-2=-3-2=-5\\\\x=0\\y=3(0)-2=0-2=-2](https://tex.z-dn.net/?f=x%3D-1%5C%5Cy%3D3%28-1%29-2%3D-3-2%3D-5%5C%5C%5C%5Cx%3D0%5C%5Cy%3D3%280%29-2%3D0-2%3D-2)
Range of this piece is [-5; -2)
![y=2x+3\ \text{if}\ 0\leq x](https://tex.z-dn.net/?f=y%3D2x%2B3%5C%20%5Ctext%7Bif%7D%5C%200%5Cleq%20x%3C5)
Substitute x =0and x = 5:
![x=0\\y=2(0)+3=0+3=3\\\\x=5\\y=2(5)+3=10+3=13](https://tex.z-dn.net/?f=x%3D0%5C%5Cy%3D2%280%29%2B3%3D0%2B3%3D3%5C%5C%5C%5Cx%3D5%5C%5Cy%3D2%285%29%2B3%3D10%2B3%3D13)
Range of this piece is [3; 13)
Therefore the range of the following piecewise function is:
![[-5;\ -2)\ \cup\ [3;\ 13)](https://tex.z-dn.net/?f=%5B-5%3B%5C%20-2%29%5C%20%5Ccup%5C%20%5B3%3B%5C%2013%29)
Look at the picture.
Answer:
Probability of having broken glass = 0.1933
Probability of not having broken glass = 0.8067
Step-by-step explanation:
The Treatment table in the file attached to the given question is written out and completed below;
Treatment
Response Smashed into Hit Control Total
Yes 16 7 6 29
No 34 43 44 121
Total: 50 50 50 150
Using relative frequencies,
the distribution of responses about whether there was broken glass at the accident for the subjects in this study can be computed as follows:
Probability of having broken glass = ![\dfrac{29}{150}](https://tex.z-dn.net/?f=%5Cdfrac%7B29%7D%7B150%7D)
Probability of having broken glass = 0.1933
Probability of not having broken glass = ![\dfrac{121}{150 }](https://tex.z-dn.net/?f=%5Cdfrac%7B121%7D%7B150%20%7D)
Probability of not having broken glass = 0.8067