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Vlada [557]
3 years ago
5

The volume of a fish tank is given by the function V(x)=(x+7)(x-4)(x+3). Write a function describing a fish tank that has the sa

me height but is longer in length by 3 units and wider by 2 units.
Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer:

V(x)=(x+9) * (x-4) * (x+6)

Step-by-step explanation:

A fish tank is normally in the shape of a rectangular prism. The volume of a rectangular prism can be calculated using the following formula

V = w * h * l

where w represents the width, h represents the heigh, l represents the length, and V represents the volume of the rectangular prism/fish tank. Therefore, we can use the function provided in the question and simply add 3 units to the length and 2 units to the width in order for it to work for our new fish tank.

V(x)=(x+9) * (x-4) * (x+6)

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jenyasd209 [6]

Answer: 6%

Step-by-step explanation:

2/50 walk, that's the same as 4/100 or 4%

1/50 bike, that's the same as 2/100 or 2%

4/100 + 2/100 = 6/100 or 6%

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4 years ago
Pls help .................................
Sophie [7]

Answer:

60

Step-by-step explanation:

yeah I looked it up but like that's what u have to do to not fail lol

4 0
3 years ago
If b+3/7=2/5 then which of the following is true
spin [16.1K]
Let multiply by 35 both sides of the equation
35b+35*3/7=35*2/5
35b+15=14
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7 0
4 years ago
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

#SPJ1

4 0
2 years ago
6/8 and 24/40 are they proportional
saul85 [17]

Answer:

no they are not

Step-by-step explanation:

6 0
3 years ago
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