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MAXImum [283]
2 years ago
8

Please help with math, due soon. Worth lots of points.

Mathematics
1 answer:
Dahasolnce [82]2 years ago
4 0

Answer:

5) 3x-4x

6) 7+5x-9x

7) 16r+6-1-32r

8) 19x-1-2x

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Initial value problems dy/dx+2y=3. Y(0)=1
Pavel [41]

The initial value equation is y = \frac 12(3 - e^{-2x})

<h3>How to solve the initial value?</h3>

The equation is given as:

\frac{dy}{dx} +2y = 3

Where

Y(0) = 1

Subtract 2y from both sides in the equation

\frac{dy}{dx}  = -2y + 3

Rewrite as:

\frac{dy}{-2y + 3}  =  dx

Integrate both sides of the equation

-\frac 12\ln|-2y + 3| = x + C_o

Multiply through by -2

\ln|-2y + 3| = -2x + C_1

Take the exponent of both sides

-2y + 3 = Ce^{-2x

Next, we solve for C under the initial condition Y(0) = 1.

This gives

-2(1) + 3 = Ce^{-2 * 0

Evaluate

-2 + 3 = C

Solve for C

C = 1

Substitute C = 1 in -2y + 3 = Ce^{-2x

-2y + 3 = e^{-2x

Next, we solve for y

y = \frac 12(3 - e^{-2x})

Hence, the initial value equation is y = \frac 12(3 - e^{-2x})

Read more about initial value at:

brainly.com/question/16945606

#SPJ1

3 0
1 year ago
A girl owns 2 pairs of pants, 1 shirts, 1 ties, and 5 jackets. how many different outfits can the girl wear to school if each ou
MariettaO [177]
2 x 1 x 1 x 5 = 10.......
5 0
2 years ago
A = ?<br> b = ?<br> Please explain as well :)
sweet [91]

Answer:

a = 25 , b = 14

Step-by-step explanation:

For A

a/5 + 3 = 8

a/5 = 8 - 3

a/5 = 5

Cross multiply

a = 5 * 5

a = 25

For B

3b/7 - 1 = 5

3b/7 = 5 + 1

3b/7 = 6

Cross multiply

3b = 42

b = 42 / 3

b = 14

Hope it will help

5 0
3 years ago
Look at the attachment<br>Simplified it too <br>pls take it seriously ​
Phantasy [73]

\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}

\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}

\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}

\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)

5 0
1 year ago
(−1)^3⋅(−1)^2<br> simplify
Nastasia [14]
When simplified the answers results in
= -1
8 0
2 years ago
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