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mafiozo [28]
3 years ago
6

A rectangular carpet has a perimeter of 194 inches. The length of the carpet is 67 inches more than the width. What are the dime

nsions of the​ carpet?
Mathematics
1 answer:
lianna [129]3 years ago
3 0

Answer:

The dimensions of rectangle are:

Width = 15 inches

Length = 82 inches

Step-by-step explanation:

Perimeter of rectangle = 1944 inches

Let

Width of rectangle = w

Length of rectangle = w+67

We need to find the dimensions (length and width) of the carpet

The formula used will be: Perimeter\:of\:rectangle=2(Length+Width)

Putting values and finding dimensions

Perimeter\:of\:rectangle=2(Length+Width)\\194=2(w+67+w)\\194=2(2w+67)\\194=4w+134\\Swirching\:sides\\4w+134=197\\Subtracting\:134\:on\:both\:sides\\4w+134-134=194-134\\4w = 60\\Divide\:both\:sides\:by\:4\\\frac{4w}{4}=\frac{60}{4}\\w=15

So, we get w = 15

Now, finding length : w+67 = 15+67 = 82

Therefore the dimensions of rectangle are:

Width = 15 inches

Length = 82 inches

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182/n = 13

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If a+b+c=6,ab+bc+ca=11,then what is a3+b3+c3-3abc
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3 years ago
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Emily has a box where she stores her toys, the box has a height of 24 inches, a length of 40 inches, and a width of 10 inches. W
emmainna [20.7K]

Answer:

2)

Step-by-step explanation:

Volume of box = length * width * height

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4 years ago
Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)
Helen [10]

Answer:

The binomial in expanded form is (0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}.

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form (a + b)^{n} can be expanded by using the following identity:

(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k} (1)

If we know that a = p = 0.3 and n = 5, then the expanded form of the binomial is:

(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}

(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}

8 0
3 years ago
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