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3 years ago

Will mark a Brainiest

Mathematics

1 answer:

Xelga [282]3 years ago

6 0

Answer:

37.5%

Step-by-step explanation:

you have 8 slices that should represent 100% so 100 divide 8 is 12.5

12.5 multiply by the three red sections you have then you get 37.5%

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

3 0

3 years ago

Using the order of operation which should be done first to evaluate 6+(-5-7)/2-8(3)?

valentinak56 [21]

Answer:

$\frac{3}{11}$

Step-by-step explanation:

=> $\frac{6+(-5-7)}{2-8(3)}$

=> $\frac{6+(-12)}{2-24}$

=> $\frac{6-12}{-22}$

=> $\frac{-6}{-22}$

=> $\frac{3}{11}$

6 0

3 years ago

Robert and Jason want to buy a group ticket package for football game package a cost 276 and includes two tickets for each of si

8_murik_8 [283]

Package A = $276 for 12 tickets (2 x 6) // 276 divided by 12 = $23 per ticket
Package B = $336 for 16 tickets (2 x 8) // 336 divided by 16 = $21 per ticket
$23 - $21 = $2

Package A charges $2 more per ticket.

5 0

3 years ago

Could someone please help me answer both questions!

Nady [450]

Answer:

1. $m = 2n$

2. $m = 3n + 1$

Step-by-step explanation:

1. 8 = 4 * 2; 10 = 5 * 2; 18 = 9 * 2....

2. 4 = 1 * 3 + 1; 7 = 2 * 3 + 1; 10 = 3 * 3 + 1....

3 0

3 years ago

What is the equation of the line that is perpendicular to the line through (1,-4) and (-2,2) and passes through the x-intercept

ss7ja [257]

Answer:

y=- $\frac{1}{2}$ x+ $\frac{3}{2}$

Step-by-step explanation:

First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find

m=(y2-y1)/(x2-x1)

=(2-(-4))/(-2-1)

=6/-3

=-2

in this equation the slope is 2, and to find the first equation, use y=mx+b

use the point (1, -4) to find b

-4=(2)(1)+b

-4=2+b

b=-6

the first equation of the line is y=2x-6

to find the x intercept of that line substitute 0 for y

0=2x-6

2x=6

x=3

the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2

for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b

y=mx+b

0=(-1/2)(3)+b

b=3/2

thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=- $\frac{1}{2}$ x+3/2

8 0

3 years ago