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Tanzania [10]
3 years ago
9

Will mark a Brainiest

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

37.5%

Step-by-step explanation:

you have 8 slices that should represent 100% so 100 divide 8 is 12.5

12.5 multiply by the three red sections you have then you get 37.5%

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A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
Using the order of operation which should be done first to evaluate 6+(-5-7)/2-8(3)?
valentinak56 [21]

Answer:

\frac{3}{11}

Step-by-step explanation:

=> \frac{6+(-5-7)}{2-8(3)}

=> \frac{6+(-12)}{2-24}

=> \frac{6-12}{-22}

=> \frac{-6}{-22}

=> \frac{3}{11}

6 0
3 years ago
Robert and Jason want to buy a group ticket package for football game package a cost 276 and includes two tickets for each of si
8_murik_8 [283]
Package A = $276 for 12 tickets (2 x 6) // 276 divided by 12 = $23 per ticket
Package B = $336 for 16 tickets (2 x 8) // 336 divided by 16 = $21 per ticket
$23 - $21 = $2

Package A charges $2 more per ticket.


5 0
3 years ago
Could someone please help me answer both questions!
Nady [450]

Answer:

1. m = 2n

2. m = 3n + 1

Step-by-step explanation:

1. 8 = 4 * 2; 10 = 5 * 2; 18 = 9 * 2....

2. 4 = 1 * 3 + 1; 7 = 2 * 3 + 1; 10 = 3 * 3 + 1....

3 0
3 years ago
What is the equation of the line that is perpendicular to the line through (1,-4) and (-2,2) and passes through the x-intercept
ss7ja [257]

Answer:

y=-\frac{1}{2}x+\frac{3}{2}

Step-by-step explanation:

First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find

m=(y2-y1)/(x2-x1)

  =(2-(-4))/(-2-1)

  =6/-3

  =-2

in this equation the slope is 2, and to find the first equation, use y=mx+b

use the point (1, -4) to find b

-4=(2)(1)+b

-4=2+b

b=-6

the first equation of the line is y=2x-6

to find the x intercept of that line substitute 0 for y

0=2x-6

2x=6

x=3

the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2

for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b

y=mx+b

0=(-1/2)(3)+b

b=3/2

thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-\frac{1}{2}x+3/2

8 0
3 years ago
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