All categories

2 years ago

Please help, and please explain how you got the answer

Mathematics

1 answer:

Vesna [10]2 years ago

3 0

Answer: i think it is D

Step-by-step explanation:

You might be interested in

5+6(2x-1) <br> i need this like now pls

Crank

Answer:

Step-by-step explanation:

5 + 6 = 11 x 2 - 1 = 21 therefore its 21

5 0

2 years ago

4c=-40 i don't know this and i need help<br> ill do what i can in return

melamori03 [73]

Answer:

4c=-40

Divide boyh sides by 4

c=-40/4

c=-10

8 0

2 years ago

Read 2 more answers

Ise the terms 4, 12a, 6, 2a, and 24 to make equivalent expressions

Sedaia [141]

Answer:

12a + 24 = 6(2a + 4) is the equivalent expressions

Step-by-step explanation:

Given the terms ; 4, 12a, 6, 2a, and 24

There are two terms with unknown = 12a and 2a

but 12a = 2a x 6 .........(1)

from the last term = 24 = 6 x 4 ...........(2)

add both equation 1 and 2 = 12a + 24

12a + 24 = 6(2a + 4) is the equivalent expressions .

to VERIFY; Use a = 2

substitute into the expression ; LHS = RHS

= 12(2) + 24 = 24 + 24 = 48 (LHS)

FOR RHS = 6(2a+4) = 6(2x2 + 4)

= 6(4+4) = 48

Hence LHS = RHS

6 0

3 years ago

Michaela works in a bank she is paid £19200 per annum how much does she get per month

Step2247 [10]

in a year she earns=19200

So in a month she earns=19200/12

=1600

So she earns 1600 every month.

If the answer is correct then make me brain list.please

4 0

3 years ago

A study was done to determine the average number of homes that a homeowner owns in his or her lifetime. For the 60 homeowners su

const2013 [10]

Answer:

D) (3.67, 4.73)

Step-by-step explanation:

Confidence Interval for the true average number of homes that a person owns in his or her lifetimecan be calculated using M±ME where

M is the average number of home owned (4.2)

ME is the margin of error from the mean

And margin of error (ME) can be calculated as

ME= $\frac{z*s}{\sqrt{N} }$ where

z is the corresponding statistic in the given confidence level(1.96)

s is the standard deviation of the sample(2.1)

N is the sample size (60)

Putting the numbers we get ME= $\frac{1.96*2.1}{\sqrt{60} }$ ≈0.53

Then the 95% confidence interval is 4.2±0.53 or (3.67, 4.73)

6 0

2 years ago