Here is the answer toke a second to remember but here u go
Answer:
a. 0.4
b. 0.6
c. 0.6493
Step-by-step explanation:
p(checking work email) = p(A) = 0.40
p(staying connected with cell phone) = p(B) = 0.30
p(having laptop) = p(c) = 0.35
p(checking work mail and staying connected with cell phone) = p(AnB) = 0.16
p(neither A,B or C) = p(AuBuC)
= 1-42.8%
= 0.572
p(A|C) = 88% = 0.88
p(C|B) = 70% = 0.7
a. What is the probability that a randomly selected traveler who checks work email also uses a cell phone to stay connected?
p(B|A) = p(AnB)/p(A)
= 0.16/0.4
= 0.4
b. What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected?
p(B|C) = P(C|B)p(B)/p(C)
= 0.7x0.3/0.35
= 0.6
c. If the randomly selected traveler checked work email and brought a laptop, what is the probability that he/she uses a cell phone to stay connected?
p(A|BnC)
= P(BnAnC)/p(AnC)
= p(AnC) = p(A|C).p(C)
= 0.88x0.35
= 0.308
p(AnBnC) = p(AuBuC)-p(a)-p(b)+ p(AnB)+p(AnC)+p(BnC)
p(BnC) = 0.7x0.3
= 0.21
p(AnBnC) = 0.572-0.4-0.3-0.35+0.16+0.308+0.21
= 0.2
p(A|BnC) = 0.2/0.308
= 0.6493
Answer:
SNITCHY SNATCH
Step-by-step explanation:
I actually don't know how to show how to graph it. Sorry. But I can give a few coordinates. For y < 1/3x + 3: (-1,2 2/3) (0,3) (1,3 1/3). For y > -2/3x - 3: (-1,-2 1/3) (0,-3) (1,-3 2/3).
#6. the answer is 12 it increases by 4 every time
#8. the answer is every week he runs his miles increase by 5
If you would like to find the area of the base of the fountain, you can calculate this using the following steps:
1 2/3 ft * 2 2/3 ft = 5/3 * 8/3 = 40/9 = 4 4/9 square feet
The area of the base of the fountain is 4 4/9 square feet.
