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aliina [53]
3 years ago
15

Which of the following would be a correct interpretation of a​ 99% confidence interval such as 4.1​5.6? Choose the correct answe

r below. A. We are​ 99% confident that the interval from 4.1 to 5.6 actually does contain the true value of . B. It means that​ 99% of sample means fall between 4.1 and 5.6. C. It means that​ 99% of all data values are between 4.1 and 5.6. D. There is a​ 99% chance that will fall between 4.1 and 5.6.
Mathematics
1 answer:
Alik [6]3 years ago
3 0

Answer:

A. We are​ 99% confident that the interval from 4.1 to 5.6 actually does contain the true value of population mean.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

99% confidence interval means that we are 99% sure that this interval contains the population mean.

Interval between 4.1 and 5.6.

So the correct answer is given by option A.

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3 years ago
On a recent day, one U.S dollar was worth 0.64 euros. If you were to exchange 126 euros on that day, how many U.S. dollars would
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Answer: $196.88

Step-by-step explanation:

It is given that the rate of 1 US dollar = 0.64 euros.

Then, 1 euro = \frac{1}{0.64}\text{ dollars}

⇒ 1 euro =1.5625 dollars

Now, 126 euros = 126\times1.5625

\Rightarrow126\text{euros} =196.875\approx196.88\text{ dollars}

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4 years ago
What is the product? startfraction 4 k 2 over k squared minus 4 endfraction times startfraction k minus 2 over 2 k 1 endfraction
Tcecarenko [31]

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1}  is the expression \frac{2}{k+2}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the expression:

(\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} \\\\This\ can\ be\ simplified\ to:\\\\(\frac{2(2k+1)(k-2)}{(k+2)(k-2)(2k+1)}) \\\\=\frac{2}{k+2}

The product of the expression (\frac{4k+2}{k^2-4})* \frac{k-2}{2k+1} is the expression \frac{2}{k+2}

Find out more on equation at: brainly.com/question/2972832

#SPJ4

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