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VladimirAG [237]
3 years ago
8

64 41 Solve for <1. « 1 = [?] 720 35°

Mathematics
2 answers:
malfutka [58]3 years ago
8 0

Answer:

\displaystyle \angle1 =  {73}^{ \circ}

Step-by-step explanation:

remember that,

the sum of the interior angles of a triangle is 180°

Thus our equation is

\displaystyle \angle1 +  {72}^{ \circ}  +  {35}^{ \circ}  =  {180}^{ \circ}

simplify addition:

\displaystyle \angle1 +  {107}^{ \circ} =  {180}^{ \circ}

cancel 107° from both sides:

\displaystyle \angle1 =  {73}^{ \circ}

RoseWind [281]3 years ago
5 0

Step-by-step explanation:

Answer:

Solution given:

<1+72+35°=180°[ interior angle of a triangle is 180]

<1=180-107

<1=73 °

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AURORKA [14]

Answer:

8 is the only one that will work

Step-by-step explanation:

(f o g)(x)=f(g(x)).

So this means the x will first be plug into g.

So let's check your choices.

g(6)=1/(6-6)=1/0 so 6 is not in the domain of g which means it isn't in the domain of (f o g).

g(8)=1/(8-6)=1/2  so this is a number so 8 is in the domain of g,

Let's check if 1/2 is in the domain of f.

f(1/2)=sqrt(6*1/2)=sqrt(3) so this is a number so since 1/2 is in the domain of f then 8 is in the domain of (f o g).

g(4)=1/(4-6)=1/(-2)=-1/2 so 4 is in the domain of g,

f(-1/2)=sqrt(6*-1/2)=sqrt(-3) so this is a problem because you can't square root negative numbers so -1/2 isn't in the domain of f, and therefore 4 isn't in the domain of (f o g).

g(2)=1/(2-6)=1/-4=-1/4 so 2 is in the domain of g.

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4 0
4 years ago
find the area of a regular pentagon inscribed in a circle whose equation is given by (x-4)^2 + (y+2)^2=25
makkiz [27]
The radius is √25=5 in this case.
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the area of each triangle is (1/2)*2*5*Sin36*5*Cos36
the total area of the 5 triangles is: 5*(1/2)*2*5*Sin36*5*Cos36
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3 years ago
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2 years ago
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erica [24]

Answer:

30 will be in each bag

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Step-by-step explanation:

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