A-artificial I-intelligent
Answer:
double the bandwidth assigned per channel to 40 MHz
Explanation:
The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.
It is a code for representing 128 English characters as numbers, with each letter assigned a number from 0 to 127. For example, the ASCII code for uppercase M is 77. Most computers use ASCII codes to represent text, which makes it possible to transfer data from one computer to another.
So here is the code in Python:
n = 0.00 #this is a float because there are some numbers that are decimals.
while n < 20: #n which is 0.00 and while it is lower than 20 if runs the code below
n = n + 1 #it will add 1 to n everything it runs the code.
k = n / 2 #it will divide whatever n is everytime by 2
print(str(n) + '/2: ') # it's printing the number it's on
print(k) # prints the answer for the n.
You can change n to add by any, make n any num instead of 0.00 and you can change the while condition from n < 20 to any other logical statement. If you want to get creative you can take 2 inputs for numbers and make one of them the starting number and other one is the ending number. Also make sure to make n a number lower than you starting point because if you set n as your starting point then it will skip it.
Answer:
C. Mean
Explanation:
Mean = (∑
)/N
Median = central values when data is sorted
Mode = most repeated value
Standard deviation = 
In standard deviation, formula you may see that deviation is being calculated from the mean (central location). But here we take square of the value before adding all of them.
But if we just take 
, it would be equal to zero.
<u>EXAMPLE</u>
Take 4, 9, 5 as data
mean = (4+9+5)/3 = 18/3 = 6
sum of deviations from mean = (4-6)+(9-6)+(5-6) = (-2)+(3)+(-1) = 0
