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3 years ago

Mallanie 2 years older then Bill . Bill is 27 years old

Mathematics

2 answers:

dlinn [17]3 years ago

7 0

really?, 27+2=29, 29 is youre answer.

Paladinen [302]3 years ago

4 0

Considering that she is 2 years older that would make her 29 because 27+2=29

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Jenny bought 0.18lb of penny candy. Will bought 0.9lb of penny candy. Who bought more?

Natasha2012 [34]

Answer:

will

Step-by-step explanation:

jenny bought 18/100

will bought 9/10

3 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

The cost of a car rental is $30 per day plus 18c per mile. You are on a daily budget of $75. Write and solve an inequality to

Tanzania [10]

Answer:

2. 5 miles

Step-by-step explanation:

Given that:

Rental cost = $30

Cost per mile driven = 18 cent

Daily budget = $75

Greatest distance you can drive each day while staying within budget :

Rental cost + (cost per mile driven * distance) ≤ daily budget

$30 + 18d ≤ $75

18d ≤ 75 - 30

18d ≤ 45

d ≤ 45 / 18

d ≤ 2.5

Greatest distance you can drive each day while staying within budget is 2.5 miles.

8 0

2 years ago

Hello? STOP RIGHT THERE.... Please help me with this.

matrenka [14]

Answer: THE ANSWER IS 2 :)

Step-by-step explanation:

3(q+2) Do distributive property

3q=6 Divide 3q to both side

3q = 3q

q= 2 This is the answer

6 0

2 years ago

PLASE ANSWER THIS QUESTION I GIVE YOU 18 POINTS

sukhopar [10]

Answer:

(a) 144

(b) 117

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

(a)

$72 = 2^3 \times 3^2$

$144 = 2^4 \times 3^2$

$LCM = 2^4 \times 3^2 = 8 \times 9 = 144$

(b)

$39 = 3 \times 13$

$117 = 3^2 \times 13$

$LCM = 3^2 \times 13 = 117$

(c)

$72 = 2^3 \times 3^2$

$90 = 2 \times 3^2 \times 5$

$LCM = 2^3 \times 3^2 \times 5 = 360$

(d)

$84 = 2^2 \times 3 \times 7$

$147 = 3 \times 7^2$

$LCM = 2^2 \times 3 \times 7^2 = 588$

(e)

$152 = 2^3 \times 19$

$288 = 2^5 \times 3^2$

$LCM = 2^5 \times 3^2 \times 19 = 5472$

6 0

2 years ago