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BartSMP [9]
3 years ago
5

How do you put them in order correctly?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0
Square root of 75 pi squared 10
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grants plans to a factory enough water from 22 gallons in a 16% ammonia solution to make a 24% solution which equation can be us
Andreyy89
16/22=24/x

x=33

then subtract

33-22=11

11 galons should be taken out
5 0
3 years ago
g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and
allsm [11]

Answer:

Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, [ab]_K is equal to [ba]_K, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.

Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, [ab]_H = [ba]_H . Since a and b were generic elements of H, then H/G is abelian.

4 0
3 years ago
Ignore my answers but pls solve and be correct
KiRa [710]

Answer:

The first one is 60 and the second one is 12

Step-by-step explanation:

5*12=60    6*12=72     72-60=12

7 0
2 years ago
Which values of x are solutions of the equation below
Mandarinka [93]

Answer:

x = 3.3 and -0.3

Step-by-step explanation:

Given the expression

1/x-4 + x/x-2=2/x^2-6x+8

Find the LCM

x-2+x(x-4)/(x-4)(x-2) = 2/x^2-6x+8

Since the denominator, are the same they cancels out

x +1 + x(x-4) = 2

x+1 + x²-4x = 2

x²-3x + 1 - 2 = 0

x² - 3x - 1 = 0

Factorize

x =3±√9+4/2

x =3±√13/2

x = 3±3.6/2

x= 6.6/2 and -0.6/2

x = 3.3 and -0.3

4 0
3 years ago
The water level in a lake was monitored and was noted to have changed -2 1/3 inches in one year. The next year it was noted to h
Diano4ka-milaya [45]

Answer:

The total change in water level over the past 2 years is \displaystyle -4 \frac{1}{6}.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Fractions

  • Proper and Improper

Numbers

  • Least Common Multiple (LCM)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Year 1 water change:  \displaystyle -2 \frac{1}{3}

Year 2 water change:  \displaystyle -1 \frac{5}{6}

<u>Step 2: Find Total Water Change</u>

  1. [Set up] Add yearly water changes:                                                                \displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}
  2. [Fractions] Convert to improper:                                                                     \displaystyle \frac{-7}{3} - \frac{11}{6}
  3. [Fraction] Rewrite [LCM]:                                                                                  \displaystyle \frac{-14}{6} - \frac{11}{6}
  4. [Order of Operations] Subtract:                                                                       \displaystyle \frac{-25}{6}
  5. [Fraction] Convert to proper:                                                                           \displaystyle -4 \frac{1}{6}
5 0
2 years ago
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