1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mixas84 [53]
3 years ago
14

Answer fasttttttt!!!!!!!!!!​

Mathematics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

yo we cant see clearly...............

LenaWriter [7]3 years ago
4 0
I can’t see anything I would have helped you
You might be interested in
Plz answer the following file attached
Finger [1]

Answer:

i like how to tell us to answer something with no file

Step-by-step explanation:

6 0
2 years ago
Find the value of each variable. Round to the nearest tenth if
solniwko [45]

Answer:

the snnswer is 47 not no other answer

Step-by-step explanation:

8 0
2 years ago
The ordered pair (3,9) is a solution to the system of
nadya68 [22]

Answer:

(2,7) is not a solution to the given system of equations.

Step-by-step explanation:

Given system of equation is:

2x + 3 = y

2x + y = 15

To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.

Putting x=2 and y=7 in Eqn 1

2(2) + 3 = 7

4 + 3 = 7

7 = 7

Thus the ordered pair satisfies the equation

Putting x=2 and y=7 in Eqn 2

2(2) + 7 = 15

4 + 7 = 15

11 ≠ 15

The ordered pair do not satisfy the second equation.

Hence,

(2,7) is not a solution to the given system of equations.

8 0
3 years ago
The author drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 199 times. Here are the observed
Anton [14]

Answer with explanation:

An Unbiased Dice is Rolled 199 times.

Frequency of outcomes 1,2,3,4,5,6 are=28​, 29​, 47​, 40​, 22​, 33.

Probability of an Event

      =\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(1)=\frac{28}{199}\\\\P(2)=\frac{29}{199}\\\\P(3)=\frac{47}{199}\\\\P(4)=\frac{40}{199}\\\\P(5)=\frac{22}{199}\\\\P(6)=\frac{33}{199}\\\\\text{Dice is fair}\\\\P(1,2,3,4,5,6}=\frac{33}{199}

→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value

1.

(e_{1})^2=(P_{1})^2+(P'_{1})^2\\\\(e_{1})^2=[\frac{28}{199}]^2+[\frac{33}{199}]^2\\\\(e_{1})^2=\frac{1873}{39601}\\\\(e_{1})^2=0.0472967\\\\e_{1}=0.217478\\\\z_{1}=\frac{P'_{1}-P_{1}}{e_{1}}\\\\z_{1}=\frac{\frac{33}{199}-\frac{28}{199}}{0.217478}\\\\z_{1}=\frac{5}{43.27}\\\\z_{1}=0.12

→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.

2.

(e_{2})^2=(P_{2})^2+(P'_{2})^2\\\\(e_{2})^2=[\frac{29}{199}]^2+[\frac{33}{199}]^2\\\\(e_{2})^2=\frac{1930}{39601}\\\\(e_{2})^2=0.04873\\\\e_{2}=0.2207\\\\z_{2}=\frac{P'_{2}-P_{2}}{e_{2}}\\\\z_{2}=\frac{\frac{33}{199}-\frac{29}{199}}{0.2207}\\\\z_{2}=\frac{4}{43.9193}\\\\z_{2}=0.0911

Result is not significant.

3.

(e_{3})^2=(P_{3})^2+(P'_{3})^2\\\\(e_{3})^2=[\frac{47}{199}]^2+[\frac{33}{199}]^2\\\\(e_{3})^2=\frac{3298}{39601}\\\\(e_{3})^2=0.08328\\\\e_{3}=0.2885\\\\z_{3}=\frac{P_{3}-P'_{3}}{e_{3}}\\\\z_{3}=\frac{\frac{47}{199}-\frac{33}{199}}{0.2885}\\\\z_{3}=\frac{14}{57.4279}\\\\z_{3}=0.24378

Result is not significant.

4.

(e_{4})^2=(P_{4})^2+(P'_{4})^2\\\\(e_{4})^2=[\frac{40}{199}]^2+[\frac{33}{199}]^2\\\\(e_{4})^2=\frac{3298}{39601}\\\\(e_{4})^2=0.06790\\\\e_{4}=0.2605\\\\z_{4}=\frac{P_{4}-P'_{4}}{e_{4}}\\\\z_{4}=\frac{\frac{40}{199}-\frac{33}{199}}{0.2605}\\\\z_{4}=\frac{7}{51.8555}\\\\z_{4}=0.1349

Result is not significant.

5.

(e_{5})^2=(P_{5})^2+(P'_{5})^2\\\\(e_{5})^2=[\frac{22}{199}]^2+[\frac{33}{199}]^2\\\\(e_{5})^2=\frac{1573}{39601}\\\\(e_{5})^2=0.03972\\\\e_{5}=0.1993\\\\z_{5}=\frac{P'_{5}-P_{5}}{e_{5}}\\\\z_{5}=\frac{\frac{33}{199}-\frac{22}{199}}{0.1993}\\\\z_{5}=\frac{11}{39.6610}\\\\z_{5}=0.2773

Result is not significant.

6.

(e_{6})^2=(P_{6})^2+(P'_{6})^2\\\\(e_{6})^2=[\frac{33}{199}]^2+[\frac{33}{199}]^2\\\\(e_{6})^2=\frac{2178}{39601}\\\\(e_{6})^2=0.05499\\\\e_{6}=0.2345\\\\z_{6}=\frac{P'_{6}-P_{6}}{e_{6}}\\\\z_{6}=\frac{\frac{33}{199}-\frac{33}{199}}{0.2345}\\\\z_{6}=\frac{0}{46.6655}\\\\z_{6}=0

Result is not significant.

⇒If you will calculate the mean of all six z values, you will obtain that, z value is less than 2.So, we can say that ,outcomes are not equally likely at a 0.05 significance level.

⇒⇒Yes , as Probability of most of the numbers that is, 1,2,3,4,5,6 are different, for a loaded die , it should be equal to approximately equal to 33 for each of the numbers from 1 to 6.So, we can say with certainty that loaded die behaves differently than a fair​ die.

   

8 0
3 years ago
Thanks to a new conservation program, a population with only 200 individuals at the beginning of the year is growing exponential
sukhopar [10]

Answer:

0.3 per year

Step-by-step explanation:

Number of newborn per year: 200*0.5 = 100

Number of death per year:  200*0.2= 40

So, the difference between birth and death = 100-40 = 60 (people)

and the growth rate during the year is: 60/200 = 0.3

<em>Hope this answer will find you well. </em>

5 0
3 years ago
Other questions:
  • What number is 672,591 closer to
    12·2 answers
  • Eric has 4 bags of marbles and 6 single marbles how many marbles does eric have
    10·1 answer
  • What is 247,039 rounded to the nearest thousand
    13·2 answers
  • I need help please.
    7·1 answer
  • What is the slope of a line that passes through (–4,–13) and (19,11)?
    11·2 answers
  • Can someone please help
    15·2 answers
  • In an auditorium, the first row of seats has 30 seats. each row behind the first row has 4 more seats then the row in front of i
    15·1 answer
  • PLEASE SHOW FULL SOLUTIONS!!! WILL MARK BRAINLIEST!!! SHOW ALL STEPS!!! THANK YOU!!!
    9·1 answer
  • HELP ME pleaseeeee ill mark you as brainiest if I get two answers
    5·1 answer
  • HELPPPPP !!! Plzzz <br> Unit 10: circles <br> Homework 2: central angles &amp; arc measures
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!