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dybincka [34]
3 years ago
10

Find the surface area of the prism. Write your answer as a decimal.

Mathematics
2 answers:
ziro4ka [17]3 years ago
5 0
The surface of the area is 1.5
ruslelena [56]3 years ago
4 0

Answer:

1.5

Step-by-step explanation:

as i have stated before

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What is the area of the the polygon 7ft 22ft 10ft
Harman [31]

Answer:1540

Step-by-step explanation:

7x10=70

70x22=1540

3 0
3 years ago
The Cortez family spends 40% of its income rent. Which of the following are equivalent to 40%
garik1379 [7]

Answer:

2/5 or 4/10 or 40/100 or 0.4 .

Step-by-step explanation:

8 0
3 years ago
Compute |2+8i|.<br> Need help
EastWind [94]

Answer:

Step-by-step explanation:

|2+8i|=√(2²+8²)=√(4+64)=√68=2√17

5 0
3 years ago
3. Two dice are rolled. What’s the conditional probability that both dice are 5’s if it’s known that the sum of points is divisi
ArbitrLikvidat [17]

Answer:

Pr =\frac{1}{3}

Step-by-step explanation:

Given

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\} --- sample space

First, list out all outcomes whose sum is divisible by 5

A = \{(4,6), (5,5),(6,4)\}

So, we have:

n(A) = 3

Next, list out all outcomes that has an outcome of 5 in both rolls

B = \{(5,5)\}

n(B)  =1

The required conditional probability is:

Pr =\frac{n(B)}{n(A)}

Pr =\frac{1}{3}

8 0
3 years ago
A cat is stuck in a tree. A firefighters 15-foot ladder is the leaning against a tree. The ladder and the ground form a 62° angl
artcher [175]
To solve this problem you must apply the proccedure shown below:

 1. You have:

 Sinα=opposite/hypotenuse

 α=62°
 opposite=x
 hypotenuse=15 ft

 2. When you substitute the values into  Sinα=opposite/hypotenuse, you obtain:

 Sinα=opposite/hypotenuse
 Sin(62°)=x/15

 3. You must clear "x", as below:

 x=(15)(Sin(62°))
 x=13.24 ft

 The answer is. 13.24 ft
 
5 0
3 years ago
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