First you have to find the angle B (check attachment)
Then you can find the last angle inside the triangle, which I'll call C
Now you can find angle A
A quadratic equation is set up in the form of ax² + bx +c
First set equation = to 0
0= x² - 5x - 24
Next plug into quadratic formula( -b Plus or minus the √b²-4ac) ÷ 2a
[10 plus or minus √(25² - 4×1×24)] ÷ 2
Solve for inner parenthesis first
√625- 96 = √529
Now set up two equations
(10 + √529) ÷2 = x = 16.5
(10 - √529) ÷2 = x = -6.5
So therefore x = 16.5 and -6.5
Answer:
F(d) = 30 + 0.50d
Step-by-step explanation:
Given
Charges = P8.00 ---- first 4 km
Additional = P0.50
Required
Write a function to address the scenario.
Represent the whole distance covered with d.
First,we need to determine the total charges for the first four hours.
Charges = 8.00 * 4
Charges = 32.00
Next, we determine the charges for additional distance.
Charges = 0.50 * (d - 4)
d - 4 is the remaining distance after the first 4.
Charges = 0.50d - 2
The function is then written as;
F(d) = 32 + 0.50d - 2
F(d) = 32 - 2 + 0.50d
F(d) = 30 + 0.50d
Answer:
-x^2 - 11x -30
Step-by-step explanation:
Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.
ie: x(x) and x(6)
ie: x^2 + 6x
Then do the 5 times the things in the second parenthesis.
ie: 5(x) and 5(6)
ie: 5x + 30
Then add what you got from multiplying the first value to what you got from multiplying the second.
ie: x^2 + 11x + 30
This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.
ie: -x^2 - 11x -30
Answer:
Step-by-step explanation:
