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Vilka [71]
2 years ago
14

In a recent year, 31% of all college students were enrolled part-time. If 8.6 million college students were enrolled part-time t

hat
year, what was the total number of college students?
Round your answer to the nearest million.
Mathematics
1 answer:
Ronch [10]2 years ago
5 0

Answer:

28 million college students.

Step-by-step explanation:

We can represent all college students as x. This means that all part-time college students are \frac{31}{100}x. Because all part-time college students are also equal to 8.6 million, we have 8,600,000=\frac{31}{100}x. To find the number of total college students, or x, we have to multiply by 100/31 to get rid of the fraction on the other side:

8,600,00\cdot\frac{100}{31}=x

The left side of the equation evaluates as 27,741,935.5. Because we are asked to round to the nearest million, we have to round to 28 million, which is the closest.

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1. (10pts] Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}. Determine each of the following (a) An Bn
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Answer and explanation:

Given : Let A = {1, 2, 3, 4, 5}, let B = {1,4,5,7,8,9}, and let C = {2, 4, 6, 7,9}.

To find : Determine each of the following,

a) (A\cap B)\cap C

b) (A\cup B)\cap (A\cup C)

c) A - (B\cup C)

d) (A-C) (C-A)

Solution :

The union of two sets is a new set that contains all of the elements that are in at least one of the two sets.

The intersection of two sets is a new set that contains all of the elements that are in both sets.

a) (A\cap B)\cap C

A\cap B=\{1,4,5\}

Then, (A\cap B)\cap C=\{4\}

b) (A\cup B)\cap (A\cup C)

A\cup B=\{1,2,3,4,5,7,8,9\}

A\cup C=\{1,2,3,4,5,7,9\}

(A\cup B)\cap (A\cup C)=\{1,2,3,4,5,7,9\}

c) A - (B\cup C)

B\cup C=\{1,2,4,5,6,7,8,9\}

A - (B\cup C)=\{3\}

d) (A-C) (C-A)

A-C=\{1,3,5\}

C-A=\{6,7,9\}

(A-C) (C-A)=\{1,3,5\}\times\{6,7,9\}

(A-C) (C-A)=\{(1,6),(1,7),(1,9),(3,6),(3,7),(3,9),(5,6),(5,7),(5,9)\}

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