Answer:
4320 units quantities were demanded
Step-by-step explanation:
Given:

Required:
The units demanded when price = 18.00
This implies that:

So, we have:


Open bracket

Collect like terms


Solve for q


-6- -2n=3n -(6+5)
combine like terms
-6 +2n = 3n -11
subtract 2n from each side
-6 = n-11
add 11 to each side
-6 +11 = n
5 =n
Answer:
Area of label = 100 inch² (Approx.)
Step-by-step explanation:
Given:
Height of label = 8 inches
Diameter of label = 4 inches
Find:
Area of label
Computation:
Design of label = Rectangle
So,
Width of label = 2πr
Width of label = 2(3.14)(4/2)
Width of label = 2(3.14)(2)
Width of label = 12.56 inches
Area of label = Height of label x Width of label
Area of label = 12.56 x 8
Area of label = 100.48
Area of label = 100 inch² (Approx.)
Answer:
120 units ^2
Step-by-step explanation:
Volume = area of cross section x length = 1/2 x 4 x 3 x 20 = 120 unit squared
Answer: i) 30 students for chemistry
ii) 21 students for only one subject
iii) 61 students
Step-by-step explanation: from the question we got 30 students registered for chemistry. number students only for biology = (27-18) = 9
number of students only for chemistry = (30-18) = 12
number of student registered for only one subject = (12+9)= 21
number of students registered for neither two subjects = {100-(9+12+18)} = 61