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Vilka [71]
2 years ago
14

In a recent year, 31% of all college students were enrolled part-time. If 8.6 million college students were enrolled part-time t

hat
year, what was the total number of college students?
Round your answer to the nearest million.
Mathematics
1 answer:
Ronch [10]2 years ago
5 0

Answer:

28 million college students.

Step-by-step explanation:

We can represent all college students as x. This means that all part-time college students are \frac{31}{100}x. Because all part-time college students are also equal to 8.6 million, we have 8,600,000=\frac{31}{100}x. To find the number of total college students, or x, we have to multiply by 100/31 to get rid of the fraction on the other side:

8,600,00\cdot\frac{100}{31}=x

The left side of the equation evaluates as 27,741,935.5. Because we are asked to round to the nearest million, we have to round to 28 million, which is the closest.

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The formula = () − applies to the demand of a product, where q is the number of units and P is the price of one unit. How many u
UNO [17]

Answer:

4320 units quantities were demanded

Step-by-step explanation:

Given:

p = 90 (5) - \frac{q}{10}

Required:

The units demanded when price = 18.00

This implies that:

p = 18.00

So, we have:

p = 90 (5) - \frac{q}{10}

18.00 = 90(5) - \frac{q}{10}

Open bracket

18.00 = 450 - \frac{q}{10}

Collect like terms

\frac{q}{10} = 450 - 18.00

\frac{q}{10} = 432

Solve for q

q = 432 *10

q = 4320

3 0
3 years ago
-6- -2n=3n -(6+5) help lol sry I actually just need a little push on this question
jek_recluse [69]

-6- -2n=3n -(6+5)

combine like terms

-6 +2n = 3n -11

subtract 2n from each side

-6 = n-11

add 11 to each side

-6 +11 = n

5 =n

7 0
3 years ago
Read 2 more answers
What is the area of the label on a soup can that is 8 inches high and has a diameter of 4 inches? Round to the nearest hundredth
olga_2 [115]

Answer:

Area of label = 100 inch² (Approx.)

Step-by-step explanation:

Given:

Height of label = 8 inches

Diameter of label = 4 inches

Find:

Area of label

Computation:

Design of label = Rectangle

So,

Width of label = 2πr

Width of label = 2(3.14)(4/2)

Width of label = 2(3.14)(2)

Width of label = 12.56 inches

Area of label = Height of label x Width of label

Area of label = 12.56 x 8

Area of label = 100.48

Area of label = 100 inch² (Approx.)

3 0
3 years ago
Find the volume of the prism
Elza [17]

Answer:

120 units ^2

Step-by-step explanation:

Volume = area of cross section x length = 1/2 x 4 x 3 x 20 = 120 unit squared

4 0
3 years ago
- (A) The following data was received from the Student Affairs Unit of the University
ladessa [460]

Answer: i) 30 students for chemistry

ii) 21 students for only one subject

iii) 61 students

Step-by-step explanation: from the question we got 30 students registered for chemistry. number students only for biology = (27-18) = 9

number of students only for chemistry = (30-18) = 12

number of student registered for only one subject = (12+9)= 21

number of students registered for neither two subjects = {100-(9+12+18)} = 61

5 0
3 years ago
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