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DerKrebs [107]
3 years ago
15

Some pls help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
2 answers:
aliina [53]3 years ago
5 0
I believe it’s -1x - 1

Add all the x’s to -3x to get -1x

-1x -4 + 3

Now add 3 to -4

-1x - 1

Hope this helps :)
Oksi-84 [34.3K]3 years ago
4 0

Answer:

-x-1

Step-by-step explanation:

Start off by combining all the like terms.

-3x+x+x=-1x=-x

-4=3=-1

Put them all together and you get -x-1

I hope this helps, and have a great day! :)

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Line through (-4,2) with slope of 3/4 in point-slope form
Brums [2.3K]
Y - 2 = 3/4 (x + 4)
4 0
3 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
HACTEHA [7]

Answer:

(a) The value of P (X ≤ 2) is 0.8729.

(b) The value of P (X ≥ 5) is 0.0072.

(c) The value of P (1 ≤ X ≤ 4) is 0.7154.

(d) The probability that none of the 25 boards is defective is 0.2774.

(e) The expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defective boards.

The probability that a circuit board is defective is, <em>p</em> = 0.05.

The sample of boards selected is of size, <em>n</em> = 25.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={25\choose x}0.05^{x}(1-0.05)^{25-x};\ x=0,1,2,3...

(a)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

P(X\leq =x)=\sum\limits^{2}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.2774+0.3650+0.2305\\=0.8729

Thus, the value of P (X ≤ 2) is 0.8729.

(b)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = 1 - P (X < 5)

              =1-\sum\limits^{4}_{x=0}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=1-0.9928\\=0.0072

Thus, the value of P (X ≥ 5) is 0.0072.

(c)

Compute the value of P (1 ≤ X ≤ 4) as follows:

P (1 ≤ X ≤ 4) = P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

                   =\sum\limits^{4}_{x=1}{{25\choose x}0.05^{x}(1-0.05)^{25-x}}\\=0.3650+0.2305+0.0930+0.0269\\=0.7154

Thus, the value of P (1 ≤ X ≤ 4) is 0.7154.

(d)

Compute the value of P (X = 0) as follows:

P(X=0)={25\choose 0}0.05^{0}(1-0.05)^{25-0}=1\times 1\times 0.277389=0.2774

Thus, the probability that none of the 25 boards is defective is 0.2774.

(e)

Compute the expected value of <em>X</em> as follows:

E(X)=np=25\times 0.05=1.25

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{25\times 0.05\times (1-0.05)}=1.09

Thus, the expected value and standard deviation of <em>X</em> are 1.25 and 1.09 respectively.

8 0
4 years ago
How many people have been to Mexico, but not have been to Canada
Reil [10]

Answer:

3

Step-by-step explanation:

9-6=3 or 6+3=9

hope this helps

3 0
3 years ago
Read 2 more answers
4. Hakim buys n kg of rice. Vanu buys 2 kg more rice than Hakim. Kevin buys
lord [1]
Rice bought by
Hakim : n kg
Vanu : n+2 kg
Kevin : 1/5(n+2) kg

Hakim + Kevin : n + 1/5(n+2)
= n + (n+2)/5
= n/5n + n^2+2n/5n
= n+n^2+2n/5n
= 3n + n^2/5n
= 3+n/5
3 0
3 years ago
Bianca deposited $1500 into asavings account for whichsimple interest is calculatedquarterly. If her $1500 grew to$1509 after 3
Furkat [3]

Solution:

Given;

P=1500,A=1509,t=3months=0.25year\begin{gathered} A=P(1+\frac{r}{4})^{4t} \\  \\ 1509=1500(1+\frac{r}{4})^{4(0.25)} \\  \\ \frac{1509}{1500}=1+\frac{r}{4} \\  \\ 1.006-1=\frac{r}{4} \\  \\ r=4(0.006) \\  \\ r=0.024 \end{gathered}

Thus, the yearly interest rate on Bianca's account is 2.4%

6 0
2 years ago
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