Answer:

Step-by-step explanation:
Circle is centred at (0, -2)
-> h = 0 & k = - 2
radius of the circle (r) = y-coordinate of the center = - 2
Equation of circle in standard form is given as:

Plugging the values of h, k and r in the above equation, we find:
![(x-0)^2 +[y-(-2)]^2 = (-2)^2](https://tex.z-dn.net/?f=%28x-0%29%5E2%20%2B%5By-%28-2%29%5D%5E2%20%3D%20%28-2%29%5E2)

This is the required equation of circle.
Answer:
288 and 289 are the two pages.
Step-by-step explanation:
Answer:
I wish <em>i could help </em>
Step-by-step explanation:
Answer:
pythagorean theory
Step-by-step explanation:h is got it
Answer:
domain: x ≥ -5
range: y ≥ 0
Step-by-step explanation:
notice the equation contains √x + 5
since anything inside a square root must not be negative, the domain is restricted to x + 5 ≥ 0 so solving for x, we have:
x ≥ -5 as the domain.
by inspecting the graph, the range is:
y ≥ 0
i hope this helps !!