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Oksanka [162]
2 years ago
13

You and your friend are using ribbon to make cards. Your ribbon is 78 inch wide. Your friend's ribbon is 58 inch wide. How much

wider is the ribbon you are using?
Mathematics
2 answers:
Yakvenalex [24]2 years ago
4 0

Answer:

20 inches longer

Step-by-step explanation:

78-58= 20

serious [3.7K]2 years ago
4 0
20 bro come one that kindergarten math
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A sector with an area of 11/2*pi cm^2 has radius of 3 cm. What is the central angle measure of a sector in degrees?
Angelina_Jolie [31]

Answer:

Step-by-step explanation:

Area of sector = angle/360 * pi * r^2

5.5pi = angle/360 * pi * 9

5.5 = angle/360 * 9

angle = (5.5 * 360)/9 = 40 * 5.5 = 220

8 0
3 years ago
Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput
Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

P = C_{n,x}.p^{n}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so p = 0.53

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 0 successes, so x = 0.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{0}.(0.47)^{4}

P = 0.0488

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 4.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,0}.(0.53)^{4}.(0.47)^{0}

P = 0.0789

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so n = 4.

Is the probability of 4 successes, so x = 2.

P = C_{n,x}.p^{n}.(1-p)^{n-x}

P = C_{4,2}.(0.53)^{2}.(0.47)^{2}

P = 0.3723

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0
3 years ago
Identify the graph as eIdentify the graph as either y = cos x  or y = sin x
serious [3.7K]
From the graph at x = 0, y = 0


Check1:
y = cosx

0 = cos(0)
0 = 1

therefore, this is not the function

Check2:
y = sinx
0 = sin(0)
0 = 0

therefore, this is the function


Conclusion:

the function in the graph is y = sinx
4 0
3 years ago
Latasha is a waitress at Seventh Heaven Hamburgers. She wants to estimate the mean amount each group at a table leaves for a tip
elena55 [62]
Forgive me if this is wrong. I haven't done stat in a year, but comment if you need clarification!

3 0
3 years ago
Which are the best labels for each column
slega [8]

Answer:

It depends on the columns

Step-by-step explanation:

4 0
3 years ago
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