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2 years ago

Instructions: use the ratio of a 45-45-90 triangle to solve for the variables. Leave your answers as radicals in simplest form

Mathematics

1 answer:

DIA [1.3K]2 years ago

4 0

Answer:

v=14, u=14

Step-by-step explanation:

The 45-45-90 theorem states that the hypotenuse is $\sqrt{2}$ times the bases of the triangle. So, to find one of the bases, we need to divide $\sqrt{2}$ . Thus, $\frac{12\sqrt{2} }{\sqrt{2} } = 12$ .

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110 is 45% of what number

aev [14]

Answer:49.5

Step-by-step explanation:

To find the 45% of 110

45/100×110

=49.5

5 0

3 years ago

Read 2 more answers

4.33 is it heavier than 4.25 by how much

vivado [14]

Answer:

0.08

Step-by-step explanation:

4 0

3 years ago

Use technology to find points and then graph the line y=-5(x-5)+1 following the instructions below.

Svetach [21]

Given:

$y=-5(x-5)+1$

First, let us find two points from this equation.

We can set values of x and then solve for y.

Let us find the values of y when x = 1, 2, 3, 4, 5

$\begin{gathered} y=-5(x-5)+1 \\ y=-5(1-5)+1=21 \\ y=-5(2-5)+1=16 \\ y=-5(3-5)+1=11 \\ y=-5(4-5)+1=6 \\ y=-5(5-5)+1=1 \end{gathered}$

We now have a set of points:

(1, 21)

(2, 16)

(3, 11)

(4, 6)

(5, 1)

Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)

The graph would then look like this:

6 0

1 year ago

there are 2000 sheets of paper in 4 reams of paper.which of the following expresses the ratio of reams to paper?

antoniya [11.8K]

-4:2000

-2:1000

-1:500

Hope this helped☺☺

4 0

3 years ago

Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°

mote1985 [20]

Answer:

$sin(2\theta)=\frac{\sqrt{35} }{18}$

Step-by-step explanation:

Recall the formula for the sine of the double angle:

$sin(2\theta)=2*sin(\theta)*cos(\theta)$

we know that $cos(\theta)=\frac{3}{18}$ , and that $\theta$ is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what $sin(\theta)$ is:

$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

6 0

3 years ago