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3 years ago

Which values are solutions to × < 10? A. × = 1 and × = 9 B. × = 18 and x = - 11 C. × = 9 and × = 15 D. × = 15 and × = 18

Mathematics

1 answer:

katen-ka-za [31]3 years ago

8 0

Answer:

Step-by-step explanation:

you need find the smaller numbers of 10 which would be in answer A. all the other answers are bigger than 10

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PLSSSSSHELPMEWITHTHISONEQUESTIONPLEASE

Doss [256]

Answer:

She can buy no more than 22 decorations

Step-by-step explanation:

The costs for the party are food and decorations

Cost = food + decorations * costs per decoration

We can spend no more than 300

Food is 75

Decorations are 10 each

Let d= the number of decorations

300 >= 75 + 10 * d

Subtract 75 from each side

300-75 >= 75-75 + 10 * d

225 >= 10d

Divide each side by 10

225/10 >=10d/10

22.5 >=d

She can buy no more than 22 decorations

7 0

3 years ago

Solve the proportion 20/3=?/6

Zepler [3.9K]

It equals 40/6. I hope this helps. Good luck!

7 0

3 years ago

Read 2 more answers

chantal volunteered to bring 1 gallon of freshly squeezed orange juice to a picnic.the local grocery store sells 4-pound bags of

pochemuha

(128 oz) * (2 oranges)/(5 oz) * (1 bag)/(11.5 oranges) * $3.49/bag ≈ $15.54

Note that we have assumed 11.5 oranges per bag, and that partial bags are available.

If Chantal must buy whole bags of oranges, 5 bags will be needed and the cost will be $17.45.

6 0

4 years ago

Write the equation of a line that passes through (-1,3) (0,8)

gizmo_the_mogwai [7]

You'll be using point slope form to solve this.

As the name suggests, you'll need the slope as well as a point. To find the slope use the slope formula: $\frac{y_2-y_1}{x_2-x_1}$

Plug in the points.

$\frac{8-3}{0-(-1)} =\frac{5}{1} =5$

The slope of this line is 5.

Point slope form is y-y1 = m(x-x1), so plug in the slope and a point into this equation. I'll use (0,8).

y-(8) = 5(x-(0))

1. Write this out without parentheses.

y-8 = 5(x)

2. Multiply 5 and x.

y-8 = 5x

3. Add 8 to both sides.

y = 5x+8

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Answer is:

y = 5x+8

6 0

4 years ago

Solve for y x=y^2+4y

Lorico [155]

$x=y^2+4y\\ y^2+4y-x=0\\\Delta=4^2-4\cdot1\cdot(-x)=16+4x\\\\
1.\ \Delta0\\
\sqrt{\Delta}=\sqrt{16+4x}=\sqrt{4(4+x)}=2\sqrt{x+4}\\
y_1=\frac{-4-2\sqrt{x+4}}{2\cdot1}=-2-\sqrt{x+4}\\
y_2=\frac{-4+2\sqrt{x+4}}{2\cdot1}=-2+\sqrt{x+4}\\$

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$x=y^2+4y\\ y^2+4y-x=0\\
y^2+4y+4-4-x=0\\
(y+2)^2=x+4\\
y+2=\sqrt{x+4} \vee y+2=-\sqrt{x+4}\\
y=-2+\sqrt{x+4} \vee y=-2-\sqrt{x+4}\\$

4 0

4 years ago