slope = 
the slope is the value of f' (36)
f(x) = √x = 
f'(x) =
= 
f'(36) =
= 
Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
Answer:- A reflection of the line segment across the line y = –x .
Explanation:-
A reflection over the line y = -x, the x-coordinate and y-coordinate interchange their places and they are negated (the signs are changed).
Given :- A line segment has endpoints at (–1, 4) and (4, 1) such that it reflects produce an image with endpoints at (–4, 1) and (–1, –4).
(-1, 4)→(-4, 1) and
(4, 1)→(-1, -4)
Thus this shows a reflection of the line segment across the line y = –x.
6.83 as a mixed number is:
6 83/100