We can write a system of equations.
x + y = 77
y = x + 5
Plug in x + 5 into the first equation:
x + y = 77
x + (x + 5) = 77
So this is our answer.
Answer:
(13/24)
Step-by-step explanation:
let’s find a common number that we can get on the denominator
4 can be multiplied to get 48
6 can be multiplied to get 48
and 8 can also be multiplied to get 48
4(12) = 48
so for the equation (1/4) the numerator and denominator will both be multiplied by 12
(1/4)x(12/12) = (12/48)
6(8)= 48
(1/6)x(8/8) = (8/48)
8(6) = 48
(1/8)x(6/6) = (6/48)
now the fractions are
(12/48)+(8/48)+(6/48)
we can add them now because they have the same denominator and we get:
(26/48)
this can be simplified if we divide both the numerator and denominator by 2 and we get
(13/24)
For the function 1,
To find the equation for this function, first you take any two points and from these points you will find the slope of line and then put it in the equation of line.
(x₁,y₁)=(0,4)
(x₂,y₂)=(1,7)
slope=m=y₂-y₁/x₂-x₁
=7-4/1-0
=3/1
=3
Equation of a line
f(x)=mx+c
where m is the slope and c is the y intercept.
f(x)=3x+4
For the function 2,
As you have given the equation of a function which is
f(x)=-2x+3
you can easily fill the table,
I do it for one value for other values you will do the same procedure.
For x=-2
f(x)=-2(-2)+3
= 7
x f(x)
-----------------
-2 7
-1 5
0 3
1 1
2 -1
For the Function 3,
You can get the values from the graph directly but you can also solve it by finding the equation first and then by putting method you get the value.
Equation of a line
f(x)=mx+c
where m is the slope and c is the y intercept.
m=(y₂-y₁)/(x₂-x₁)
(x₁,y₁)=(0,-3)
(x₂,y₂)=(6,0)
m=(0-(-3))/(6-0)
m=1/2
f(x)=1/2x-3
x f(x)
-----------------
-2 -4
-1 -7/2
0 -3
1 -5/2
2 -2
The graph of function 1 and 2 are attached below.
Answer:
dP/dt = 650t = 650(2 ) = 1,300 people/year
The rate of increasing of population at the end of the year 1992 is 1,300 people/year
Step-by-step explanation:
Given;
Population function as;
P(t) =325 t^2 + 28547
The rate of change of the population dP/dt at any given time can be given as;
Rate = change in population/change in time = dP/dt
dP/dt = 2×325t = 650t
Therefore, after 1992;
t = 1992-1990 = 2years
dP/dt = 650t = 650(2 ) = 1,300 people/year
The rate of increasing of population at the end of the year 1992 is 1,300 people/year
Y=-1/2+1, y equals negative one half plus one