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VMariaS [17]
3 years ago
9

Somebody please help me

Mathematics
2 answers:
Stella [2.4K]3 years ago
7 0

Answer:

(13/24)

Step-by-step explanation:

let’s find a common number that we can get on the denominator

4 can be multiplied to get 48

6 can be multiplied to get 48

and 8 can also be multiplied to get 48

4(12) = 48

so for the equation (1/4) the numerator and denominator will both be multiplied by 12

(1/4)x(12/12) = (12/48)

6(8)= 48

(1/6)x(8/8) = (8/48)

8(6) = 48

(1/8)x(6/6) = (6/48)

now the fractions are

(12/48)+(8/48)+(6/48)

we can add them now because they have the same denominator and we get:

(26/48)

this can be simplified if we divide both the numerator and denominator by 2 and we get

(13/24)

pantera1 [17]3 years ago
5 0

Answer:

\frac{13}{24}

Step-by-step explanation:

LCM(4, 6, 8) = 24

\frac{1}{4} + \frac{1}{6} + \frac{1}{8} = \frac{6+4+3}{24} = \frac{13}{24}

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DanielleElmas [232]
A = first piece, b = second piece, c = third piece

a + b + c = 47
b = 3a
c = 5a + 2

a + (3a) + (5a + 2) = 47.....combine like terms
9a + 2 = 47
9a = 47 - 2
9a = 45
a = 45/9
a = 5 ft

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longest piece (c) = 27 ft
7 0
2 years ago
Find the value of x in the diagram below.
dsp73

Answer:

x = 31

Step-by-step explanation:

The 2 sides are congruent, meaning the 2 angles are equal so:

47 = x + 16

subtract 16 from both sides

31 = x

5 0
2 years ago
Solve for a 4/a+4= -1/a+9
Karolina [17]

Answer:

a = -8

Step-by-step explanation:

4/a + 4 = -1/a + 9

-1(a + 4) = 4(a + 9)

-1a - 4 = 4a + 36

-5a - 4 = 36

-5a = 40

a = -8

7 0
3 years ago
Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

Seventh term = 96

a_7=a_1r(7-1)\\96=a_1r^6----eq(2)

Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

So, Common Ratio r = 2

Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

6 0
3 years ago
May someone please help me out with this problem? May you also explain it?
gavmur [86]

Answer:

Step-by-step explanation:

Given function is,

f(x) = \sqrt{x}

If the given function is vertically stretched by a scale factor of \frac{3}{2} Or 1.5,

Transformed function will be,

h(x) = \frac{3}{2}[f(x)]

h(x) = \frac{3}{2}(\sqrt{x})

Further function 'h' is shifted 1 units upwards,

g(x) = h(x) + 1

g(x) = \frac{3}{2}(\sqrt{x} )+1

Domain of the function → x ≥ 0 Or [0, ∞)

Range of the function → y ≥ 1 Or [1, ∞)

Transformations done → Parent function f(x) is vertically stretched by a scale factor of \frac{3}{2} then shifted 1 unit upward.

3 0
3 years ago
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