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VMariaS [17]
3 years ago
9

Somebody please help me

Mathematics
2 answers:
Stella [2.4K]3 years ago
7 0

Answer:

(13/24)

Step-by-step explanation:

let’s find a common number that we can get on the denominator

4 can be multiplied to get 48

6 can be multiplied to get 48

and 8 can also be multiplied to get 48

4(12) = 48

so for the equation (1/4) the numerator and denominator will both be multiplied by 12

(1/4)x(12/12) = (12/48)

6(8)= 48

(1/6)x(8/8) = (8/48)

8(6) = 48

(1/8)x(6/6) = (6/48)

now the fractions are

(12/48)+(8/48)+(6/48)

we can add them now because they have the same denominator and we get:

(26/48)

this can be simplified if we divide both the numerator and denominator by 2 and we get

(13/24)

pantera1 [17]3 years ago
5 0

Answer:

\frac{13}{24}

Step-by-step explanation:

LCM(4, 6, 8) = 24

\frac{1}{4} + \frac{1}{6} + \frac{1}{8} = \frac{6+4+3}{24} = \frac{13}{24}

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Spotlight Dance increased the number of dancers on its competition team. Last
Nana76 [90]

Answer:

80%

Step-by-step explanation:

To find percentage increase, we use the following formula:

Percentage Increase = \frac{New-Old}{Old}*100

Here

New means the latest value (which is 18 dancers)

Old means the previous value (which is 10 dancers)

The Multiplication by 100 is to convert the decimal answer to percentage.

So, we have:

New = 18

Old = 10

Now we substitute and find:

\frac{New-Old}{Old}*100\\\frac{18-10}{10}*100\\\frac{8}{10}*100\\80

So, there was an increase of 80%

3 0
3 years ago
(15pts) factor each completly
Natali [406]
Your answers:

10) (m+7)(m+8) 11) (b-10)(b+2)

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14) (7r+3)(r-2) 15) (5a+6)(a+2)

Hope it helps
5 0
3 years ago
Read 2 more answers
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

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4 years ago
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Idk! Is there a picture to show us?
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I think this is the correct answer: * Zc x (sigma/sqrt of n)
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